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2 years ago

What is the classification of the pair of angles shown?

Mathematics

1 answer:

AleksAgata [21]2 years ago

7 0

Answer:

Vertical

Step-by-step explanation:

Since both the angles are located directly opposite of each other, this is a vertical angle pair.

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The regular price of an item at a store is p dollars. The item is on sale for 20% off the regular price. Some of the expressions

s344n2d4d5 [400]

Two expressions each represent the sale price of the item are:

Expression B : 0.8p is correct

Expression D: p - 0.2p is correct

<em><u>Solution:</u></em>

The regular price of an item at a store is p dollars

The item is on sale for 20% off the regular price

Therefore,

Regular price = p dollars

Discount = 20 % of regular price

Therefore,

Discount = 20 % of p

$discount = 20 \% \times p\\\\discount = \frac{20}{100} \times p = 0.2 \times p\\\\discount = 0.2p$

Sale price = Regular price - discount price

Sale price = p - 0.2p

Thus Expression D: p - 0.2p is correct

On solving, sale price = p - 0.2p

Sale price = 0.8p

Thus expression B : 0.8p is correct

3 0

2 years ago

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

3 years ago

In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.

Crazy boy [7]

Answer:

O is in between m and p so it is 6

Step-by-step explanation:

In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.

6 0

1 year ago

8+2=16106 what does 5+4 equal?

bazaltina [42]

Is this a riddle?? Or are you really doing this :-(

3 0

3 years ago

Help ! Please ! If a/2 - b/3=1 , what is 2a+3v in terms of b?

ArbitrLikvidat [17]

A/2-b/3=1 solve for a, add b/3 to both sides

a/2=1+b/3 which is equal to

a/2=(3+b)/3 multiply both sides by 2

a=(6+2b)/3 now you can substitute this into 2a+3b giving you:

2(6+2b)/3 + 3b which is equal to

(12+4b+9b)/3

(13b+12)/3

7 0

2 years ago