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I am Lyosha [343]
2 years ago
12

What is the classification of the pair of angles shown?

Mathematics
1 answer:
AleksAgata [21]2 years ago
7 0

Answer:

Vertical

Step-by-step explanation:

Since both the angles are located directly opposite of each other, this is a vertical angle pair.

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What multiplies to get -2 and adds to get -5​
tatyana61 [14]
You would have to use the quadratic formula because it’s not a perfect square
6 0
3 years ago
Raisins, almonds, and sunflower seeds are sold together in packages of 350 g.
frosja888 [35]

Answer:

124.9g approximately 125g

Step-by-step explanation:

Sum of total ratio= 5+7+2= 14

Mass of Raisins = 5/14 x 350 = 125g

Mass of almonds = 7/12 x 350 = 175g

Mass of Sunflower = 2/12 x 350 = 50g

Total package = 125 + 175 + 50 = 350g.

You're Welcome

3 0
3 years ago
A washer and dryer cost $1000 combined. The of the washer is three times the cost of the dryer. What is the cost of the dryer?
Tasya [4]
Let “x” represent the cost of the dryer in dollars
The washer costs 3x dollars

3x + x = 1000
4x = 1000
x = 250

The dryer is $250
8 0
3 years ago
The total cost of the trip can be found by adding these components: Entrance fee per student: $5(29) Lunch costs: $4(29 + 6) Bus
N76 [4]

Given:

Entrance fee per student: $5(29)

Lunch costs: $4(29 + 6)

Bus fees: $25 + 8($2 + $3)

Total cost: 5(29) + 4(35) + 25 + 8(5)

To find:

The equivalent expressions of the total cost that use the properties of operations to simplify the math.

Solution:

We have,

Total cost = 5(29) + 4(35) + 25 + 8(5)

To simply this expression, we need to write 29 and 35 in the expand form or as the sum of their place values because it is easy to multiply a number with multiply of 10 and single digit.

Total cost = 5(20+9) + 4(30+5) + 25 + 40

Therefore, the correct option is B.

6 0
3 years ago
Read 2 more answers
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
Read 2 more answers
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