Answer:
16,384π/3
Step-by-step explanation:
V = (4/3)πr³
V = (4/3)π(16³)
V = 16,384π/3
By rewriting the weights in decimal form and applying them to the correspondent percentages, we will see that the final grade is 92.8%.
<h3>
What is Jore's final math grade?</h3>
The final grade will be given by:
G = a₁*x₁ + a₂*x₂ + ...
Where the values "a" are the weights, and the values "x" are the averages of Jeorge.
We know that the weights are:
- 30% on Quizzes.
- 10% on homework
- 40% on unit test.
- 20% on the final exam.
Then we can write the weights in decimal form:
a₁ = 0.3
a₂ = 0.1
a₃ = 0.4
a₄ = 0.2
And the scores are:
- 92% on quizzes.
- 98% on homework
- 91% on unit tests
- 95% on final exam.
So the final math grade will be:
G = 0.3*92 + 0.1*98 + 0.4*91 + 0.2*95 = 92.8%
If you want to learn more about percentages, you can read:
brainly.com/question/843074
In words it would be said Thirty nine point four
Step-by-step explanation:
1 .f(x)=
-x+1
f(-1)= (-1)-(-1)+1
f(-1)= 1+1+1
= 3
3.f(x)=-x+1
f( 1)=(1)-1+1
f( 1)=1-1+1
=1
5. f(x)=-x+1
f(3)=
-3+1
= 9-3+1
=7
2. g(x) = 5 - 3x
g( -8)=5-3(-8)
g( -8)=5+24
=29
4.g(x) = 5 - 3x
g(5)=5-3(5)
g(5)=5-15
=-10
6.g(x) = 5 - 3x
g(-3)=5-3(-3)
g(-3)=5+9
=14
