Answer:
1. r = ![\sqrt[3]{\frac{3v}{4\pi } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B3v%7D%7B4%5Cpi%20%7D%20%7D)
divide v by 4/3, this is the same as multiplying v by 3/4 so you have 3v/4
then divide v by 
so you now have 3v/4
then get rid of the ^3 on r by putting the solution for r under a ∛
2. a) The equation might need to be written in terms of a because you may not know the value of a, but you know the value of everything else. If this is the case then you can simply rewrite the equation so that you can plug it all into a calculator and avoid certain possible errors.
b)
s = ut + 1/2 
subtract ut from both sides: s - ut = 1/2
multiply both sides by 2: 2(s - ut)
divide both sides by 
: 
= a
answer: a =
I'm not entirely sure about b) for question 2 so you might wanna double check that with a friend
To solve a problem like this, you will need to use substitution or elimination. For the sake of an example I will solve this using substitution.
First, solve one of the equations for x or y:
3x-5y=-39
3x=-39+5y
X=(-39+5y)/3
Then substitute for the value of x in the second equation:
6x+2y=-42
6((-39+5y)/3)+2y=-42
Solve for y:
-78+10y +2y=-42
-78+12y=-42
12y=36
Y=3
Once you've solved for y, you can plug in it's value to find x:
X=-39+5(3)/3
X=-24/3
X=-8
So, we can conclude that the correct answer is B. (-8,3)
Heya!
Answer is 
<u>EXPLANATION</u><u> </u><u>:</u><u>-</u>
Given
x-y= -5
x-y=1³
Substitute value of x - y as 1³ in first equation,
=> x-y= -5
=> 1³ = -5
As we can't do anything more to solve, we can finally write as :
~ Benjemin360
