6(2m - 1) - 4(m + 8)

1: Explain Why (4,1) is not a solution to the equation y=3x+1

guapka [62]

1. (4,1) is not a solution because when u sub it into the equation, it does not come out correct. It would be correct if it was (1,4).

2. C = 2.50d.....where C is the cost and d is the number of drinks bought. And if u pick any number for d, then u can solve for the cost (C).

8 0

3 years ago

Read 2 more answers

Pls help meeee and if y’all want give me yalls snap or sum cus I need more help

Andreas93 [3]

Answer:

ooooooooooooo more help...

Step-by-step explanation:

anyways join my meet and ill give u my number

pls j0!n me

mnv-dyzw-eov

there will be nothing unsafe or inappropriate

8 0

2 years ago

Read 2 more answers

Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).

Vanyuwa [196]

$L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)$

$R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R$

5 0

2 years ago

Read 2 more answers

If the coordinates (-2, 1), (1, 1), and (1, 4) are translated 5 units right, the new coordinates would be ______? *If the coordi

Natali5045456 [20]

I would say B . From the 5 Units

4 0

2 years ago

Read 2 more answers

How many oz of walnuts which cost $6/oz must be added to 2 oz of peanuts which cost $12/oz to make mixed nuts which cost $8/oz

Burka [1]

Answer: 4 oz

<u>Step-by-step explanation:</u>

Create a table. Multiply across and add down (the middle column cannot be added). The Mixture line creates the equation that must be solved.

Let x represent the unknown quantity of walnuts.

$\begin{array}{c|c|c||c}&\underline{Quantity}&\underline{Cost}&\underline{Qty \times Cost}\\Walnuts&x&6&6x\\\underline{Peanuts}&\underline{\qquad 2\qquad}&\underline{\qquad 12\qquad}&\underline{\qquad 24\qquad }\\Mixture&x+2&8&6x+24\end{array}$

$.\qquad \qquad \qquad \qquad (x+2)(8) = 6x+24\\.\qquad \qquad \qquad \qquad 8x + 16 = 6x + 24\longrightarrow \text{distributed}\\.\qquad \qquad \qquad \qquad2x+16=24\qquad \longrightarrow \text{subtracted 6x}\\.\qquad \qquad \qquad \qquad 2x=8\qquad \qquad \ \longrightarrow \text{subtracted 16}\\.\qquad \qquad \qquad \qquad x=4\qquad \qquad \quad \longrightarrow \text{divided by 2}$

4 0

2 years ago