Answer is C:9
12^9/12^5 = 12^4
hope it helps
Answer:1)5x^2-11x
2) x^2-3x
Step-by-step explanation:
1)(f+g)(x)
f(x)=3x-7
g(x)= 2x-4
[(3x-7)+(2x-4)](x)
3x^2-7x+2x6^2-4x
=<u>5x^2-11x</u>
2) (f-g)(x)
[(3x-7)-(2x-4)](x)
(3x-7-2x+4)(x)
3x^2-7x-2x^2+4x
x^2-3x
The small rectangle was blown up by 5 times to turn into the bigger rectangle to put x5 in the box =)
Answer:
1/3
Step-by-step explanation:
Divide the numerator and denominator by 6.
6/18 = 1/3
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
brainly.com/question/25970931
#SPJ1
