Answer:
Option (A)
Step-by-step explanation:
A set of real numbers is a combination of both rational and irrational numbers.
But the elements in the sets of rational and irrational numbers will be different.
In short, rational and irrational number sets are the two subsets of real numbers.
Hence, the number is an element of either the set of rational numbers or the set of irrational numbers.
Option (A) is the correct option.
The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.
Domain is the values of x in the function represented by y=f(x), for which y exists.
THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".
Now we assume the and
So here since g(x) is a polynomial function so it exists for all real x.
<em> </em>does not exists when
, so the domain of f(x) is given by all real x except 6.
Now,
So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.
But domain of both f(x) and g(x) consists of the value x=4.
Hence the statement is not TRUE universarily.
Thus the given statement about the composition of function is FALSE.
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Answer:
The average rate of change for the function over the given integral
Step-by-step explanation:
Explanation
<u>Average rate of a functio</u>n:-
<u>We can define the average rate of change of a function from a to b</u>
<u></u>
Given function f(x) = eˣ
Given interval x = a = -2 and y = b = 0
f(a) = f(-2) = e⁻²
f(b) = f(0) = e⁰
The average rate of change for the function over the given integral