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Thepotemich [5.8K]

2 years ago

7

You estimate that your school is about 49 ft tall. Your school is actually 58 ft tall. Find the percent error in your estimation

.
The percent error is
%. (Round to the nearest percent as needed.)

2 answers:

LuckyWell [14K]2 years ago

5 0

Answer:

Step-by-step explanation:

.155 would be the decimal. 58-49 is 9. 9/58 to find the decimal of .155. then multiply by 100 to get 15.5% or 16%

Naddika [18.5K]2 years ago

4 0

Answer:

16%

Step-by-step explanation:

$\frac{|49-58|}{58}*100=15.5=16$

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bija089 [108]

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2 years ago

Find the probability of spinning a 2 and 4 and rolling a 6?

Tasya [4]

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Just by simply adding the two quantities you can get the net change. $67.12 +(addition sign because we want the net change) $2.56= $69.68. The last number is the net change!

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The cost of a student ticket to the schools play is $7. write an equation that correctly relates the cost,c,for particular numbe

charle [14.2K]

The independent variables are the cost for one ticket and the number of student tickets. The cost of the tickets depends on the number of student tickets being purchased. The equation would be c = 7s.

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2 years ago

There are some Nichols dimes and quarters in a large piggy bank for every two nickels there a sweetheart forever to Diane’s ther

grigory [225]

Answer:

There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.

All coins in the piggy bank worth $91.

Step-by-step explanation:

Please consider the complete question:

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes there are 5 quarters. There are 500 coins total. How many nickels, dimes, and quarters are in the piggy bank? Explain your reasoning. How much are the coins in the piggy bank worth?

Let n, d, q represent number of nickles, dimes and quarters respectively.

For every 2 nickels there are 3 dimes. We can represent this information in an equation as:

$\frac{2}{n}=\frac{3}{d}...(1)$ or

$n=\frac{2d}{3}...(1)$

For every 2 dimes there are 5 quarters. We can represent this information in an equation as:

$\frac{2}{d}=\frac{5}{q}...(2)$ or

$q=\frac{5d}{2}...(2)$

There are 500 coins total. We can represent this information in an equation as:

$n+d+q=500...(3)$

We will use substitution method to solve our given system.

Upon substituting equation (1) and equation (2) in equation (3), we will get:

$\frac{2d}{3}+d+\frac{5d}{2}=500$

Multiply the equation by 6:

$\frac{2d}{3}*6+d*6+\frac{5d}{2}*6=500*6$

$2d*2+6d+5d*3=3000$

$4d+6d+15d=3000$

$25d=3000$

$\frac{25d}{25}=\frac{3000}{25}$

$d=120$

Therefore, there are 120 dimes in the piggy bank.

Upon substituting $d=120$ in equation (1), we will get:

$n=\frac{2(120)}{3}$

$n=2(40)$

$n=80$

Therefore, there are 80 nickels in the piggy bank.

Upon substituting $d=120$ in equation (2), we will get:

$q=\frac{5d}{2}$

$q=\frac{5(120)}{2}$

$q=5(60)$

$q=300$

Therefore, there are 300 quarters in the piggy bank.

Now, we need to find the value of all coins.

We know 1 quarter is worth $0.25, so 300 quarters will be worth $\$0.25\times 300=\$75$ .

We know 1 dime is worth $0.10, so 120 dimes will be worth $\$0.10\times 120=\$12$ .

We know 1 nickel is worth $0.05, so 80 nickels will be worth $\$0.05\times 80=\$4$ .

$\text{All coins worth}=\$75+\$12+\$4$

$\text{All coins worth}=\$91$

Therefore, all coins in the piggy bank worth $91.

7 0

3 years ago

A cab charges $1.75 for the flat fee and $0.25 for each mile. write and solve an inequality to determine how many miles eddie ca

ad-work [718]

The answer is <span>a. $1.75 + $0.25x ≤ $15; x ≤ 53 miles
</span>
x - the number of miles
C - the cab charge

<span>A cab charges $1.75 for the flat fee and $0.25 for each mile: C = 1.75 + 0.25x.
</span><span>Eddie has $15 to spend. So, he cannot spend more than 15 on the cab and the maximum amount he can spend is 15. Therefore:
</span>1.75 + 0.25x ≤ 15

Now, let's solve it:
0.25x ≤ 15 - 1.75
0.25x ≤ 13.25
x ≤ 13.25 / 0.25
x ≤ 53

3 0

2 years ago