the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
The denominator is the one on the bottom so 9 is the denominator the top is the numerator
6 mins goes into 60 mins ten times.
so, first do
now 50000 crauons are being made in 1 hour but your are trying to find how many crayons are being made in 3 hours
so, you multiply
150000 is how many crayons are made in 3 hours.
Answer:
The same lines
Step-by-step explanation:
2 similar lines overlap each other, so each point on the line is a solution to the system of equations because it is a solution to "both lines".
Answer:
A) f(x)=x/(x-6)^2 over the interval [3, 5]
Step-by-step explanation:
got it right on edge :) good luck!
