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DiKsa [7]
3 years ago
8

Technology progress so new needs can be satisfied

Computers and Technology
2 answers:
snow_lady [41]3 years ago
7 0

Yes, that is definitely true.

miv72 [106K]3 years ago
6 0

Answer:

A- True

Explanation:

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Explain why it is important that the device registration is the last thing that is done in the initialization routine of a devic
melisa1 [442]

The reason why device registration is the last thing done is that if any errors happens at the time you register device, you have to undo the registration activities and as such, it is often done last.

<h3>What is role of a device driver?</h3>

The device driver is known to be the device that gives the other part  of the operating system the needed software interface or the device class.

The reason why un-registering a device must happen first in the exit routine of a device driver is because if there is an issue, one has to settle it first before registration as one does not want error.

Conclusively, If any kind of errors is seen when a person wants to register the device, the person must undo any kind of registration that has been performed before that error occurs.

Learn more about device registration from

brainly.com/question/16010611

6 0
2 years ago
Write a program that reads raw data from a file that contains an inventory of items. The items should be sorted by name, and the
Anika [276]

Answer:

//C++ code

#include<iostream>

#include<fstream>

#include<iomanip>

using namespace std;

/*===============================================*/

// a structure called prod

struct prod

{

string name;// – a string, assumed to have no spaces

double price; // –adollaramount

int inStock; // – the number of items currently in stock.

};

//Fucntion Prototypes

void readInventory(prod products[], int& size);

/*===============================================*/

/*returns: a dollar amount, the total value of the inventory*/

double totalValue(prod products[], int size);

/*===============================================*/

// Sorts the given array by name

void sort(prod products[], int size);

/*===============================================*/

/*a report to a file called “report.txt”.

When the file fails to open, print

“Unable to open output file.” and end.*/

void writeReport(prod products[], int size);

/*===============================================*/

//Function definitions

/*===============================================*/

void writeReport(prod products[], int size)

{

ofstream outfile("report.txt");

outfile << fixed << setprecision(2);

if (!outfile)

{

cout << "Unable to open output file.\n";

return;

}

outfile << "+------------------------------+\n | Current Inventory |\n\

\n+------------------------------+\nNAME PRICE #\n\

\n-------------------- ------- ---\n";

for (int i = 0; i < size; i++)

{

outfile << products[i].name << " " << products[i].price << " " << products[i].inStock << endl;

}

outfile << "+------------------------------+\n";

outfile << "Number of products: " << size << endl;

outfile << "Inventory total value: " << totalValue(products, size) << endl;

cout << "Report written to file\n";

//close the output stream

outfile.close();

}

/*===============================================*/

void sort(prod products[], int size)

{

for (int i = 0; i < size; i++)

{

for (int j = i+1; j < size; j++)

{

if (products[i].name > products[j].name)

{

//swapping

prod temp = products[i];

products[i] = products[j];

products[j] = temp;

}

}

}

}

/*===============================================*/

double totalValue(prod products[], int size)

{

double total = 0;

for (int i = 0; i < size; i++)

{

total += products[i].inStock * products[i].price;

}

return total;

}

/*===============================================*/

void readInventory(prod products[], int& size)

{

// Open a file called “inventory.txt”

//and read the data from the file into the partial array

//.If the file fails to open,

//print “Unable to open input file”

//and set the number of products to 0.

size = 0;

ifstream inFile("inventory.txt");

if (!inFile)

{

cout << "Unable to open input file.\n";

return;

}

string name;

double price;

int qunatity;

while (inFile >> price >>qunatity >>name)

{

if (price != -1 && qunatity != -1 && name != "endofdata")

{

products[size].name = name;

products[size].inStock = qunatity;

products[size].price = price;

size++;

}

}

cout << "inventory read\n";

//close the stream

inFile.close();

}

/*===============================================*/

int main()

{

//declares a partial array of products

prod products[100];

int size;

// invokes readInventory()

readInventory(products, size);

// invokes sort()

sort(products, size);

// invokes writeReport()

writeReport(products, size);

// ends with the standard system pause.

system("pause");

return 0;

}

please see attachment for inventory text and output.

4 0
3 years ago
A line graph is a great tool for showing changes over time. Why is a line graph better than other graphs at showing this type of
Marizza181 [45]

Answer:

Line graphs allow us to see overall trends such as an increase or decrease in data over time. Bar graphs are used to compare facts.

3 0
3 years ago
What type of Microsoft Server serves as an email server?
Misha Larkins [42]
I have a feeling you're looking for Microsoft Outlook.
4 0
3 years ago
Read 2 more answers
For each of the following application areas state whether or not the tree data structure appears to be a good fit for use as a s
Cerrena [4.2K]

Answer:

a) Chess game moves:- Tree data structure is not a good fit.

b) Public transportation paths:- Tree data structure is not a good fit.

c) Relationshi[p among computer files and folders:- Tree data structure is a good fit.

d) Genealogical information:- Tree data structure is a good fit.

e) Parts of books:- Tree data structure is a good fit.

f) Programming language history:- Tree data structure is not a good fit.

g) Mathematical expression:- Tree data structure is a good fit.

Explanation:

a) Chess game moves:- Tree data structure is not a good fit. Since in tree data structure moving backward or sharing the node is not that much easy. Presume, In chess, you have to check any box is empty or not. Here, Graph is the best fit.

b) Public transportation paths:- Tree data structure is not a good fit. whenever shortest path, routes, broadcast come always graph is a good option. Because in the tree you don't know how many time you visit that node

c) Relationshi[p among computer files and folders:- Tree data structure is a good fit. Since they have a predefined route. Go to 'c' drive. Open a particular folder and open a particular file.

d) Genealogical information:- Tree data structure is a good fit. Since genealogical information also has a predefined route. Here, the Graph is not suitable.

e) Parts of books:- Tree data structure is a good fit. Since manages the chapters and topics are not that much complex. You can see any book index which is in a very pretty format.

f) Programming language history:- Tree data structure is not a good fit. To store the history of the programming language we need some unconditional jumps that's why the tree is not suitable.

g) Mathematical expression:- Tree data structure is a good fit. The tree is suitable in some cases. We have an expression tree for postfix, prefix.

5 0
3 years ago
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