Question

Which set of ordered pairs does not represent a function? { ( − 3 , − 1 ) , ( 8 , − 1 ) , ( 0 , − 5 ) , ( − 9 , − 2 ) } {(−3,−1),(8,−1),(0,−5),(−9,−2)} { ( 5 , 9 ) , ( − 3 , − 5 ) , ( 0 , 4 ) , ( − 9 , 9 ) } {(5,9),(−3,−5),(0,4),(−9,9)} { ( 9 , 0 ) , ( − 5 , 4 ) , ( 5 , 0 ) , ( 6 , 3 ) } {(9,0),(−5,4),(5,0),(6,3)} { ( 2 , 8 ) , ( 2 , 1 ) , ( − 9 , − 5 ) , ( − 8 , 9 ) } {(2,8),(2,1),(−9,−5),(−8,9)} Submit Answer

Answer 1

Answer:

$\{(2,8),(2,1),(-9,-5),(-8,9)\}$ is not a function

Step-by-step explanation:

Given

$\{(-3,-1),(8,-1),(0,-5),(-9,-2)\}$

$\{(5,9),(-3,-5),(0,4),(-9,9)\}$

$\{(9,0),(-5,4),(5,0),(6,3)\}$

$\{(2,8),(2,1),(-9,-5),(-8,9)\}$

Required

Which is not a function

A function is of the form $(x,y)$

Assume a function is:

$\{(x_1,y_1),(x_2,y_2),(x_3,y_3).....,(x_n,y_n)\}$

In simple terms:

For an ordered pair to be regarded as a function, no x value must be repeated

Analyzing the options:

1. $\{(-3,-1),(8,-1),(0,-5),(-9,-2)\}$

This is a function because none of the x values (-3, 8, 0 and -9) appeared more than once

2. $\{(5,9),(-3,-5),(0,4),(-9,9)\}$

This is a function because none of the x values (5, -3, 0 and -9) appeared more than once

3. $\{(9,0),(-5,4),(5,0),(6,3)\}$

This is a function because none of the x values (9, -5, 5 and 6) appeared more than once

4. $\{(2,8),(2,1),(-9,-5),(-8,9)\}$

This is not a function because one of the x values (2) appeared more than once.

i.e.

$(2,8)$   and   $(2,1)$