1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anastasy [175]
3 years ago
7

Ms. Figgs asked 25 students in her 7th-grade homeroom to select their favorite cookie. The results are recorded in the table bel

ow. Based on the results, how many students will NOT select chocolate chip as their favorite cookie, if there are 250 students in the seventh grade?
Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0

Step-by-step explanation:

Can you show a picture of the table, I can't help if I don't see the whole problem

You might be interested in
Based on the graph, which inequality is correct for a number that is to the left of -4?
vitfil [10]
B -4 is closer to zerowhich makes it bigger
7 0
3 years ago
Dennis is cutting construction paper into rectangles for a project he needs to cut one rectangle that is 12 inches times 15 1/4
Nataly_w [17]

Answer:

Dennis need 288.91 square inches of construction paper for his project.

Step-by-step explanation:

Dennis is cutting construction paper into rectangles for a project.

He needs to cut one rectangle that is 12 inches times 15 1/4 inches

First convert the mixed fraction to improper fraction

15\frac{1}{4} = \frac{(15\times4) + 1}{4} = \frac{61}{4}

So the area of 1st rectangle is

A_1 = 12\times \frac{61}{4} = 183 \: in^{2}

He needs to cut another rectangle that is 10 1/3"" x 10 1/4""

The symbol " means inches

First convert the mixed fraction to improper fraction

10\frac{1}{3} = \frac{(10\times3) + 1}{3} = \frac{31}{3}

10\frac{1}{4} = \frac{(10\times4) + 1}{4} = \frac{41}{4}

So the area of 2nd rectangle is

A_2 = \frac{31}{3}\times \frac{41}{4} = 105.91 \: in^{2}

The total construction paper needed for this project is

A = A_1 + A_2\\\\A = 183 + 105.91\\\\A = 288.91 \: in^{2}

Therefore, Dennis need 288.91 square inches of construction paper for his project.

6 0
4 years ago
Is there a proportional relationship? A salt water solution for and aquarium calls for 35 parts of salt to 1000 parts of water t
morpeh [17]

Answer:

Yes

Step-by-step explanation:

To check proportionality :

35 α 1000

35 = 1000k

k = constant of proportionality ;

Divide both sides by 1000 to obtain k

35 / 1000 = 1000k / 1000

0.035 = k

For the ratio Given :

Ratio of 7 parts of salt and 200 parts of water

7 : 200

7 / 200

= 0.035

Since,

k = 0.035 ; 7 / 200 = 0.035

Hence, a proportional relationship exists.

7 0
3 years ago
What is the complimentary angle of 72 degrees
Irina18 [472]

Answer: 18°

Step-by-step explanation:

Complementary angles are any two angles whose sum is 90 degrees. Hence, if angles x and y are complimentary, we can say

x + y = 90°

Therefore, the complimentary angle of 72° is obtained by subtracting 72° from 90°

i.e 90° - 72° = 18°

Thus, the complimentary angle of 72° is 18°

4 0
4 years ago
Read 2 more answers
Expand the following expression: 4 (2k + j)
Nadya [2.5K]

Answer:

4(2k + j) = 8k + 4j

Step-by-step explanation:

4(2k + j)

Distribute in the 4.

4 * 2k + 4 * j

Multiply 4 and 2k.

8k + 4 * j

Multiply 4 and j.

8k + 4j

3 0
2 years ago
Read 2 more answers
Other questions:
  • ILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST
    12·2 answers
  • A triangle has sides of lengths 8,15 and 17. is it a right triangle? explain
    13·1 answer
  • PLZ HELP QUICK
    6·1 answer
  • How can you estimate to find the percent of a number? Please give a full explanation.
    7·1 answer
  • 11+3(9-6)-4=<br> Please do it step by step.
    6·2 answers
  • If g(x) = (24 – x)2 + 7, what is<br> the value of g(6)?<br> O 250<br> O-2<br> O 243<br> O 331
    11·1 answer
  • Find c
    10·1 answer
  • Solve for v: v-6+=-9+3v-6-4
    11·1 answer
  • Tony spent $60.54 and bought 3 packs of notebooks and a
    10·2 answers
  • Need help with Trig fast
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!