Question

Factor completely 8y^2-33y+25

Answer 1

We are given the equation 8y^2 - 33y + 25.

First multiply the first and the last coefficients: 8x25 = 200

Now we need to factorize 200 such that these factors add up to the middle coefficient -33. By trial and error, we find that

200 = (-8) x (-25)

and

-25 - 8 = -33

So,
8y^2 - 33y + 25
= 8y^2 - 25y - 8y + 25
= y(8y - 25) - (8y - 25)
= (y-1)(8y - 25)