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dangina [55]
3 years ago
11

I need help with a question.

Mathematics
1 answer:
Over [174]3 years ago
7 0
The answer is x =-2
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Why is the answer 350m by 700m?
fomenos

Answer:245000m

Step-by-step explanation:

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3 years ago
ANSWER = MY ETERNAL LOVE determine an equation of the line which is the perpendicular bisector of the segment whose endpoints ar
katen-ka-za [31]

Answer:

Perpendicular Bisector Equation: y = 12x - 9.500

Step-by-step explanation:

Let find out the midpoint for given coordinates as follows:

[(-5+7)/2, (3 +2)/2]

= (2/2, 5/2)

= (1,5/2)

The midpoint coordinates are (1,5/2) means (x1 , y2)

2. Find the slop of line for given coordinates as follows:

(2-3)/(7-(-5)

= -1/12

3. Find the negative reciprocal as follows

-1/12

= 12 (m)

4. Now find the perpendicular bisector equation as follows:

y – y1 = m ( x – x1)

y – 3 = 12 (x – (-5)

y = 12x - 9.5

6 0
3 years ago
Simplify w/ positive values
Licemer1 [7]
\bf \sqrt{\cfrac{3x^5}{75x^9}}\qquad 
\begin{cases}
75=3\cdot 5\cdot 5\to 3\cdot 5^2\\
x^9\to x^{5+4}\to x^5\cdot x^4
\end{cases}\qquad thus
\\\\\\\\
\sqrt{\cfrac{3x^5}{3\cdot 5^2\cdot x^5\cdot x^4}}\implies \sqrt{\cfrac{3x^5}{3x^5}\cdot \cfrac{1}{5^2x^4}}\implies \sqrt{1\cdot \cfrac{1}{5^2x^4}}
\\\\\\\\
\sqrt{\cfrac{1}{5^2x^4}}\qquad 
\begin{cases}
1^2\to 1\\
x^4\to x^{2\cdot 2}\to (x^2)^2
\end{cases}\qquad thus
\\\\


\bf \sqrt{\cfrac{1}{5^2x^4}}\implies \sqrt{\cfrac{1^2}{5^2(x^2)^2}}\implies \sqrt{\cfrac{1^2}{(5x^2)^2}}\implies \sqrt{\left( \cfrac{1}{5x^2} \right)^2}
\\\\\\
\cfrac{1}{5x^2}
6 0
4 years ago
What is a circumference of a circle with radius 8 meters?
aalyn [17]
C≈50.27m

Hope this helps you out
3 0
4 years ago
Read 2 more answers
Algebra 1 Solving Linear Expressions.What is 9x-6=-3x+30?
Allushta [10]


The answer is x=6.     9x-6=3x+30

                                    9x-3x-6=3x-3x+30

                                     6x-6=0 +30

                                     6x-6 + 6= 0 + 30 +6

                                     6x=36

                                      6x/6=36/6

                                         x=6 

4 0
3 years ago
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