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3 years ago

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Triangles ABC and EDC are similar . find the measure of angle D.

1 answer:

ratelena [41]3 years ago

4 0

Since you are given that the triangle are similar, by definition of similar, we know that corresponding angles are congruent and corresponding sides are proportional.
The ORDER of the similarity statement is paramount.
Triangle ABC is similar to triangle EDC means that:
Angle A = Angle E
Angle B = Angle D
Angle C = Angle C

Angle B = 62 degrees so Angle D = 62 degrees.

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Alexandra [31]

Answer:

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The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 8 to 5. If there were 1

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3 years ago

There were 239 people at Travis Scott concert.Admission to get the drive in concert was $15 for adults and $5.50 for children th

svlad2 [7]

Answer: There are 152 adults and 87 children.

Step-by-step explanation:

Let x= Number of adults

y= Number of children

As per given, we have

x+y = 239 (i)

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Multiply 5.50 on both sides of (i) , we get

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3 years ago

A data set includes 40 pulse rates of men, and those pulse rates have a mean of 67.3 beats per minute and a standard deviation o

Dafna11 [192]

Answer:

The 99% confidence interval of the standard deviation of the pulse rates of men is

$[ 7.949 \ \ , \ 14.387 ]$

Step-by-step explanation:

From the question we are told that

The sample size is n = 40

The mean is $\= x = 67.3 \ beats \ per \ minute$

The standard deviation is $s = 10.3 \ beats \ per \ minute$

Generally the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 40- 1$

=> $df = 39$

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the chi distribution table the critical value of at a degree of freedom of is

$X^2 _{\frac{\alpha }{2} , 39} = 65.476$

Generally from the chi distribution table the critical value of at a degree of freedom of is

$X^2 _{1- \frac{\alpha }{2} , 39} = 19.996$

Generally the 99% confidence interval of the standard deviation of the pulse rates of men is mathematically represented as

$s \sqrt{\frac{n- 1}{X^2_{1- \frac{\alpha }{2} , n-1} } }\ \ , \ s \sqrt{\frac{n- 1}{X^2_{\frac{\alpha }{2} , n-1} } }$

=> $10.3 \sqrt{\frac{40- 1}{65.476} }\ \ , \ 10.3 \sqrt{\frac{40- 1}{19.996} }$

=> $[ 7.949 \ \ , \ 14.387 ]$

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3 years ago

Need help ! Will reward brainliest to the correct answer ! See posted picture above for question !

natka813 [3]

Here is all my work along with some steps. Hope it helps.

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