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Serggg [28]
3 years ago
6

Is this relations a function? Justify your answer. ​

Mathematics
2 answers:
castortr0y [4]3 years ago
6 0

Answer:

lets gooo

Step-by-step explanation:

n200080 [17]3 years ago
4 0

Answer:

A

Step-by-step explanation:

There need to be more matching points, but there aren't, therefore, its A

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Find The difference 25(d−10)−23(d+6) is
Vesna [10]

Answer:

2d-388 or 2(d-194)

Step-by-step explanation:

25(d-10)-23(d+6)

25d-250-23d-138

25d-23d-250-138

2d-250-138

2d-388

factor out or simplify,

you get 2(d-194)

8 0
2 years ago
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Please help wehn we are done we get jeporady and its graded too i cave an F pls help
fgiga [73]

Answer:

look it up

Step-by-step explanation:

go on your phone

click google

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don't be trash player

7 0
3 years ago
Match the equations of the lines with their graphs.
nika2105 [10]

Answer:1. y = 2x - 3

2. y= 2x + 3

3. y = -2x + 3

4. y = -2x - 3

Step-by-step explanation:

5 0
2 years ago
If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n st ?
yulyashka [42]

Answer:

A) None

Step-by-step explanation:

1) s^t shoudnt neccesarily be a factor of nst, for example, if s = 3, t = 4, and n = 12, then both s and t are factors of n, but 3^4 = 81 is not a factor of nst = 144.

2) (st)^2 shoudnt neccesarily be a factor of nst. Let s be 4, let t be 6, and let n be 12. Then n is a factor of both s and t, but (st)^2 = 24^2 is not a factor of nst = 12*24. In fact, it is a greater number.

3) Again, s+t isnt necessarily a factor of nst, let s be 2 and t be 3. Then both s and t are factor of n = 12. However 5 = s+t is not a factor of nst = 72.

So, neither of the three options is guaranteed to be a factor of nst. In fact, for s = 4, t = 6, and n = 12, none of the three options are valid.

4 0
3 years ago
Please solve this I need it for class.
Agata [3.3K]

Answer:

<em>A =1</em>

<em>B = 9</em>

<em>C = 8</em>

<em>D = 1</em>

4 0
2 years ago
Read 2 more answers
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