Answer:
The statement, (1- <em>α</em>)% confidence interval for (μ₁ - μ₂) does not contain zero is TRUE.
Step-by-step explanation:
The hypothesis for a test is defined as follows:
<em>H</em>₀: μ₁ = μ₂ vs. <em>H</em>ₐ: μ₁ ≠ μ₂
It is provided that the test was rejected st the significance level <em>α</em>%.
If a decision is to made using the confidence interval the conditions are:
If the null hypothesis value is not included in the (1 - <em>α</em>)% confidence interval then the null hypothesis will be rejected and vice versa.
In this case the null hypothesis value is:
<em>H</em>₀: μ₁ - μ₂ = 0.
If the value 0 is not included in the (1 - <em>α</em>)% confidence interval for the difference between two means, then the null hypothesis will be rejected.
Thus the statement, (1- <em>α</em>)% confidence interval for (μ1- μ2) does not contain zero is TRUE.
Answer:
Step-by-step explanation:
Sounds as tho' possible answer choices were listed. Please, share them without being asked to do so. Thank you.
7√(x²) 7√(x²)
------------- = ----------------------
5 √(y³) 5√( y^(3/2) )
We want to get the fractional exponent out of the denominator. To do this, multiply both numerator and denominator by y^(1/2):
7√(x²) 7√(x²) y^(1/2) 7√(x²)·y^(1/2) 7x√y
------------- = --------------------- * ----------- = --------------------- = ----------
5 √(y³) 5√( y^(3/2) ) y^(1/2) 5 √(y²) 5y
This is the final answer. We have succeeded in removing radicals / fractional exponents from the denominator.
The simplify answer is 550.
15/7 might be the answer I’m not sure
The length is the long side and the width is the short side.
To find the area you multiply the 2 measurements.
