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3 years ago

What would 19 and 4/5 be as a decimal like this:

Mathematics

1 answer:

allochka39001 [22]3 years ago

4 0

19.8

I really didn't understand your question, but if you could give me more details, that'd be great.

#I'm11

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Please please help me no links

Finger [1]

Given:

In triangle ABC, AB = AC, AD is angle bisector and measure of angle C is 49 degrees.

To find:

The value of x and y.

Solution:

In triangle ABC,

$AB=AC$ (Given)

So, triangle ABC is an isosceles triangle and by the definition of base angles the base angles of isosceles triangle are congruent.

In isosceles triangle ABC,

$\angle B\cong \angle C$

$m\angle B\cong m\angle C$

$m\angle B\cong 49^\circ$

The angle bisector of an isosceles triangle is the median and altitude of the triangle. So, the angle bisector is perpendicular to the base.

$m\angle ADB=90^\circ$

$x^\circ=90^\circ$

In triangle ABD,

$m\angle DAB+m\angle ABD+m\angle ADB=180^\circ$ [Angle sum property]

$y^\circ+49^\circ+x^\circ=180^\circ$

$y^\circ+49^\circ+90^\circ=180^\circ$

$y^\circ=180^\circ-49^\circ-90^\circ$

$y^\circ=41^\circ$

Therefore, the correct option is B.

3 0

3 years ago

A bookstore had 81 copies of a magazine. Yesterday the bookstore sold

olga2289 [7]

Answer:

The question is unclear, but if the book store sold 9 copies total, they sold 2 yesterday.

Step-by-step explanation:

I am not sure how many copies were sold in total but here is how you can solve it- Get the total amount of copies and subtract the number of copies sold in total. Then get the difference and subtract 7 from it. The difference is your answer.

7 0

3 years ago

I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a

solong [7]

Answer:

$\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}$

Step-by-step explanation:

$40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4$

7 0

3 years ago

A jewelry box is b2 inches long, 3c2 inches wide, and 2c1 inches tall. Which of the following are correct? Select ALL that apply

Mariulka [41]

9514 1404 393

Answer:

B, F

Step-by-step explanation:

The volume is the product of the dimensions:

V = LWH

V = (b^2)(3c^2)(2c^1) = (3·2)(b^2)(c^(2+1))

V = 6b^2·c^3 . . . . . matches B

For b=3 and c=2, the volume is ...

V = 6(3^2)(2^3) = 6(9)(8)

V = 432 . . . . cubic inches . . . . matches F

6 0

3 years ago

Need answer asap

jolli1 [7]

Answer:

1/4 will cancel

Step-by-step explanation:

Simplify the fraction

-----

140

Divide the top and bottom by 7

---

divide the top and bottom by 5

----

4 0

2 years ago

Read 2 more answers