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vovikov84 [41]
3 years ago
14

PLEASE HELP ASAP!!!!!!

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0

Answer: B) 4

Step-by-step explanation:

Sorry for the late response. It should be B) because of this.....

1,000 x 4% x 4 years would equal 160

Add that to the original amount and you get 1,160. I just took this TGA and I’m waiting for results. Hope this works for you.

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Solve the inequality. –2 < 4x – 10 < 6
Arlecino [84]
-2 < 4x - 10 < 6
+10. +10. +10
8 < 4x < 16
÷4. ÷4. ÷4
2 < x < 4
5 0
3 years ago
Read 2 more answers
Solve, 3y(4y−1)−2y(6y−5)=9y−8(3+y)
igomit [66]

Answer:

3y(4y-1)-2y(6y-5)=9y-8(3+y)

12y∧2-3y-12y∧2+10y=9y-24-8y

12y∧2-12y∧2-3y+10y=9y-8y-24

7y=y-24

7y-y=-24

6y=-24

y=-24/6=-4

Step-by-step explanation:

5 0
3 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
4 years ago
4-2x divided by 5 plus 3 =9
choli [55]
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5 0
4 years ago
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A manager wants to build 3-sigma x-bar control limits for a process. The target value for the mean of the process is 10 units, a
lubasha [3.4K]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Mean = 10

Sample size = 9

Standard deviation = 6

We need to find the upper and lower control limits.

so, Lower limit would be

\bar{x}-3\dfrac{\sigma}{\sqrt{n}}\\\\=10-3\times \dfrac{6}{\sqrt{9}}\\\\=10-6\\\\=4

Upper limit would be

\bar{x}+3\dfrac{\sigma}{\sqrt{n}}\\\\=10+3\times \dfrac{6}{\sqrt{9}}\\\\=10+6\\\\=16

Hence, Third option is correct.

3 0
4 years ago
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