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The decimal .67 can be written as which fraction? A) 67 10,000 B) 67 1,000 C) 67 100 D) 67 10

ss7ja [257]

That would be C because there are two zeros right?
So you move two decimal places from 67.
And you get 0.67

5 0

3 years ago

Michelle had 600 fish to feed the dolphins in a zoo. Each dolphins ate the same number of fish. There are 9 dolphins in all. How

garik1379 [7]

600 fish / 9 dolphins = 66.667

9 fish * 66 = 594 fish

600 fish - 594 fish = 6 fish

there are 6 fish left

4 0

3 years ago

A coach needs both small and large cones to set up an obstacle course. The coach knows that there are fewer than 30 cones in the

Pepsi [2]

Since they are FEWER than 30 total cones, the sum of x small cones and y large one must be LESS THAN 30: x+y <30
He needs AT LEAST a dozen (12), so that means that 12 will work or more than 12:
$y \geqslant 12$

5 0

3 years ago

Read 2 more answers

Suppose the number of inches of rainfall each year in a city is normally distributed. For a random sample of years, the confiden

quester [9]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Or equivalently:

$\bar X \pm ME$

For this case we have the interval given (3.9, 7.7) and we want to find the margin of error. Using the property of symmetry for a confidence interval we can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{7.7-3.9}{2}= 1.9$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Or equivalently:

$\bar X \pm ME$

For this case we have the interval given (3.9, 7.7) and we want to find the margin of error. Using the property of symmetry for a confidence interval we can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{7.7-3.9}{2}= 1.9$

4 0

3 years ago

What is the equation of the line for this function? (0, 0), (2, 1), (4, 2), (6, 3).

aleksley [76]

The equation of the line is $y=\frac{1}{2}x$