All categories

3 years ago

The value of x satisfying both the equations 4x – 5 = y and 2x – y = 3, when y = -1 is

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

x = 1

Step-by-step explanation:

4x-5=y

4x-5= -1

4x = -1+5

4x=4

x=1

2x-y=3

2x-(-1)=3

2x+1=3

2x= 3-1

2x= 2

x=1

since the two answers for x are the same therefore:

x = 1

You might be interested in

Simplify:<br><br> {(-8)^-4 ÷ 2^-8}^2

Aleksandr-060686 [28]

Answer:

ok so first we have to do whats in the brackets then we have to do to exponits so first

(-0.00024414062divided by 0.00390625)^2

-0.06249999872^2

-0.00390624984

Hope This Helps!!!

8 0

2 years ago

Read 2 more answers

What are the names of three planes that contain point B? a planes ABD, EFG, and BDH b planes ABD, AEF, and DHF c planes CDH, ABF

Radda [10]

Answer

Sol: The correct answer is b. three planes that contain point B are ABD, AEF and DHF.

8 0

3 years ago

4 - 2(x-4)/ 3= 3(2x+5)/2<br>pls answer fast

adell [148]

Answer:

-21/22

Step-by-step explanation:

1.Apply fraction cross multiply

2. Simplify

3.Expand

4.Subtract 24 from both sides

5.simplify

6. Subtract 18x form both sides

7.Simpiify, then divide both sides by -22to get answer.

7 0

3 years ago

Solve the inequality: n - 7 > -4

ollegr [7]

Answer:

n-7>-4

n-7+7>-4+7

n>-4+7

n>3

3 0

3 years ago

Please answer this mathematical problem.

n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

$\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}$

$\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }$

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

$\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}$

5 0

2 years ago