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3 years ago

15

keisha weighs 100 pounds and gains 5 pounds per month. kyra weighs 130 and loses 2 pounds per month. after how many months will

they weigh the same weight

1 answer:

stira [4]3 years ago

4 0

Answer:?

Step-by-step explanation:

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1 > -1/2x + 5 solve for x

RUDIKE [14]

Answer:

x is greater than 8

Step-by-step explanation:

6 0

1 year ago

I have to write the slope and equation of each line pictured in y = mx + b form.

Brut [27]

Answer:

y=7/3x+8

Step-by-step explanation:

You have to start at the 3and rise all the way to the 8 which is 7 and then run which is 3 so the slope mx is 7/3x. To find b which is the y intercept find the point where the line hits the y-axis.

5 0

2 years ago

How many unique triangles can be made when one angle measures 90 degrees and another angle is half that measure?

goldenfox [79]

I believe only two but im not really sure on that

7 0

3 years ago

If I have (-2, 7) and (6, y) distancia = 10 . How can I find y?

shusha [124]

Answer:

y = 13

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 2, 7) and (x₂, y₂ ) = (6, y)

d = $\sqrt{(6+2)^2+(y-7)^2}$ , that is

d = $\sqrt{8^2+(y-7)^2}$ = 10

$\sqrt{64+(y-7)^2}$ = 10 ← square both sides

64 + (y - 7)² = 100 ( subtract 64 from both sides )

(y - 7)² = 36 ← take the square root of both sides

y - 7 = 6 ( add 7 to both sides )

y = 13

7 0

2 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

2 years ago

Read 2 more answers