Answer:No
Step-by-step explanation:
They come out to different answers
Option A. All the real values of x where x < -1
Procedure
Solve the inequality:
(x -3)(x+1)>0
That happens in two cases.
1) When both factors >0
x-3>0 and x+1>0
x>3 and x >-1
The intersection is x >3
2) When both factors <0
x-3<0 and x+1<0
x<3 and x<-1
the intersection is x<-1.
We have obtained that the function is positive for the intervals x < -1 and x > 3. But in one of those intervals the function is decresing and in the other is increasing.
You can recognize that the function given is a parabola and, because the coefficient of the quadratic term is positive, the parabola opens upward. Then the function is decreasing in the first interval and increasing in the second interval.
Answer:
Step-by-step explanation:
If the given is x^2 then the degree is 2.
Degree: 4 - x^2 = 2.
It is what is on the x to the highest power. If the question was
x^3 - 3x^2 + 2x + 4
The the degree would be 3
For the graph in the figure
we know that
the function is a quadratic equation ( vertical parabola) open up
so
The vertex is a minimum
the vertex is the point 
The domain x of the function is all real numbers-------> (-∞,∞)
The range is the interval--------> [0,∞)
therefore
Statements
A) The range is the set of all real numbers
Is false
B) The domain is the set of all real numbers
Is true
C) The domain is the set of all real numbers greater than or equal to zero
Is false
D) The range is the set of all real numbers greater than or equal to zero
Is true
Answer:
.um g o o g l e look it u p I do that.
