Answer:
Step-by-step explanation:
We have to write an equation of a line which passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1)
Now, equation (1) is in the slope-intercept form and the slope of the line is 3.
Let, m is the slope of the required line.
So, 3m = -1
{Since, the product of the slopes of two perpendicular straight lines is -1}
⇒ 
Therefore, the equation of the required line in slope intercept form is
{Where c is a constant}
Now, this above equation passes through the point (-9,2) point.
So, 
⇒ 2 = 3 + c
⇒ c = - 1
Therefore, the equation of the required straight line is (Answer)
Answer:
3.5% of 20, (0.035)*20, and 7% of 10
Step-by-step explanation:
Converting the mixed number (3 1/2) to a decimal yields 3.5, so 3.5% of 20 is correct.
3 1/2 is not equal to 3 1/2%, so 3 1/2 * 20 is not correct.
Converting the percentage to a decimal yields .035 which makes .35 too large, so (0.35) * 20 is not correct.
Changing the percentage to a decimal yields .035, so (0.035) * 20 is correct.
If you divide 20 by 2, you get 10, and if you multiply 2 by 3 1/2, you get 7. The 2 remains part of the expression, so it is equal to 3 1/2 of 20.
When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula
for
0=ax²+bx+c
so for
0=-16t²+25t+3
a=-16
b=25
c=3
so
it has to be a positive time
so it will hit the ground after
seconds
Answer: H
Step-by-step explanation:
