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3 years ago

How is 3/5 and 8/10 Are equivalent fractions?

1 answer:

4 0

Hi!

These are not <span>equivalent fractions because 8/10 reduces to 4/5, not 3/5, therefore, they are not </span>equivalent.

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90 students take a test.

Anika [276]

Answer:

Step-by-step explanation:

If there are 90 students and the ratio of boys to girls is 3:2, that means 3x+2x=90

Combine like terms: 5x=90

x=18

2x (girls)=36

3x (boys)=54

1/3 of the boys scored full marks, so 54/3=18 boys scored full marks

The number of girls who scored full marks is half of the number who did not score full marks means that 1/3 of the girls scored full marks. 36/3=12, so 12 girls scored full marks.

(I don't know what the question is sorry if it's incorrect but there's not enough information)

Hope this helps!

5 0

3 years ago

A rectangular rug has a perimeter of 220 feet. The width of the rug is two feet less than the length. Find the length and the wi

Gekata [30.6K]

Answer:

The length is 56 and the width is 54.

Step-by-step explanation:

The perimeter of a rectangle is 2x+2y (width and length on both sides). so 2x+2y=220. Also x=y-2, because the width is 2 feet less than the length. Fill x=y-2 in 2x+2y=220 and we get 2(y-2)+2y=220. 2y-4+2y=220. 4y=216. y=54. Fill in y=54 in 2x+2y=220 and we get 2x+2(54)=220. 2x=220-2(54)=112. x=56.

7 0

3 years ago

20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st

Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that $p = 0.13$

14 drivers are stopped

This means that $n = 14$

(a) None will have an invalid license.

This is $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423$

(b) Exactly one will have an invalid license.

This is $P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977$

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

$P(X < 2) + P(X \geq 2) = 1$

We want $P(X \geq 2)$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56$

8 0

3 years ago

working together, shawn and hector can install a tile floor in 6 hours. it would take shawn 9 hours to do the job alone. what is

Vikki [24]

First, let x be the number of hours it will take for Hector to finish the same job alone. This means that every hour, Hector can do 1/x of the job. The amount of work done by Shawn and Hector in 6 hours should be equal to 1 complete work. This can be expressed as,
(1/9 + 1/x)(6) = 1
The value of x is 18. Thus, Hector can to 1/18 of the job in one hour.

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