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docker41 [41]
3 years ago
7

Help pls _____________

Mathematics
2 answers:
madam [21]3 years ago
8 0

Answer:

Kate,Benjamin,Logan

Step-by-step explanation:

erik [133]3 years ago
4 0
Kate, benjamin, logan
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-1+-3<-0.5+-0.5

Step-by-step explanation:

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Step-by-step explanation:

The pendulum swings over an angle of 2×(2°30') or 5° so we need to convert this to radian measure first:

5° × \left(\dfrac{\pi}{180°}\right) = 0.0873\:\text{rad}

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3 years ago
A password contains exactly 7 letters. How many passwords are possible if letters cannot be used more than once?
DerKrebs [107]

Answer:

B

Step-by-step explanation:

This is a combination problem. For the first letter, there are 26 possible letters in the alphabet to use. For the second, we cannot use the letter used in the first, so there are only 25 possible letters. Repeat this for the remaining 5 letters.

1st - 26

2nd - 25

3rd - 24

4th - 23

5th - 22

6th - 21

7th - 20

To find the number of possible passwords, simply multiply all these numbers together. 26*25*24*23*22*21*20 = 3,315,312,000. Therefore B is the correct answer.

8 0
2 years ago
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the ratio of hard problems to easy problems was 23 to 7. how many easy problems were there if the total number of problems was 9
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I just know the answer is five

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