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garri49 [273]
3 years ago
9

Find the distance between the points ( – 8,1) and ( – 2,9).

Mathematics
1 answer:
Simora [160]3 years ago
4 0

Answer:

Find the distance between the points (

Step-by-step explanation:

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Misty correctly determined the equation of the linear function represented by the table of values below to be y = negative 2 x +
olasank [31]

Answer:

C

Step-by-step explanation:

y = mx + c

m = (y2 - y1 )/ (x2 - x1)

using (1 , 7) & (2,5)

y2 = 5 y1 = 7 so y2 -y1 = -2

x2 = 2 x1 = 1 so x2 - x1 = 1

m - -2/1 = -2

y = -2x + c

when x =1 y = 7

so 7 = -2 + c

=> c =9

y = -2x + 9

if ordered pairs (2, 5) and (4, 1) used

m = (1-5)/(4-2)

=> m = -4/2

=> m = -2

y = -2x + c

for x =2 y =5

5 = -2*2 + c

=> c = 9

y = -2x + 9

she would have got same equation

3 0
3 years ago
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PLEASE HELP ME WITH MY MATH
Alina [70]

Answer:

Step-by-step explanation:

1)

y is 3 times more than x.

X=0 Y=0  3x0=0

X=1  Y=3

X=2 Y=6

X=3 Y=9

X=4 Y=12

Then just plot it as co-ordinates (x,y)

2)

Y is 1/4 of x. Divide by 4

X=0 Y=0

X=4 Y=1

X=8 Y=2

X=12 Y=3

X=16 Y=4

Then just plot it as co-ordinates (x,y)

8 0
3 years ago
guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

#SPJ4

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Evaluate f(-3) and f(5) with the equation f(x)=3x+5
OLga [1]
See photos for solutions and steps :)

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Solve for z −cz+6z=tz+83
Alborosie

Answer: z=83/c - 7 + t

Step-by-step explanation:

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