The roots are 1 +√7 and 1 -√7.
<h3>What is Quadratic equation?</h3>
A quadratic equation in the variable x is an equation of the form ax² + bx + c= 0, where a, b, c are real numbers, a≠0
Given equation:
y= x²+2x-6
First,
Half the coefficient of x and add and subtract the square of (b/2)
y= x²+2x-6+(1)²-(1)²
y= x²+2x+(1)² -6 -(1)²
y= (x+1)² -7
Now, equate y=0
(x+1)² -7 =0
(x+1)² = 7
x+1= ±√7
x=1 ±√7
Hence, the roots are 1 +√7 and 1 -√7.
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Answer:
Option B
y coordinate is 0
Step-by-step explanation:
We have in two dimension rectangular system of coordinates with two mutually perpendicular lines called x and y axis.
X axis is the horizontal line and y the vertical line, the point of intersection of these two lines is called origin with x=0: y=0
To the right of origin, positive values are marked and left negative. Similarly for y axis, above origin positive values and below negative values.
Thus we have along x axis, y values to be 0
Hence any point on x coordinate will be of the form (a,0) where a can be any real number
So option B is right
Answer:
B.120 feet
Step-by-step explanation:
12 × 20 × 10 = 120
Answer:
Center = (5, -2) and radius = √33
Step-by-step explanation:
The equation of a circle is given by the formula;
(x-a)² + (y-b)² = r² ; where (a,b) is the center of the circle and r is the radius of the circle.
In this case;
2x² - 20x + 2y² + 8y =40 ;
Dividing both sides of the equation by 2 we get;
x² - 10x + y² + 4y = 20
we can then use the completing the square on both x and y terms.
x² - 10x + y² + 4y = 20
x² + 2(-5)x + 25 + y² + 2(2) y + 4 = 20 +9 + 4
In standard form we get;
(x-5)² + (y+2)² = 33
Therefore;
Center = (5, -2) and radius = √33
