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Elden [556K]
3 years ago
8

How do you put f(8)=-1,f(6)=0 into point slop form?​

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

y + 1 = -1/2(x - 8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

f(8) = -1 → Coordinate (8, -1)

f(6) = 0 → Coordinate (6, 0)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute [SF]:                    m=\frac{0+1}{6-8}
  2. Add/Subtract:                      m=\frac{1}{-2}
  3. Simplify:                               m=\frac{-1}{2}

<u>Step 3: Write Function</u>

<em>Substitute into general form.</em>

  • Point 1: y + 1 = -1/2(x - 8)
  • Point 2: y = -1/2(x - 6)
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