y = - 
x + 
The equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 6x + 12y = 9 into this form
subtract 6x from both sides
12y = - 6x + 9 ( divide all terms by 12 )
y = - 
x + 
( which simplifies to )
y = - x +
The product of 8 and 90 is 720 because 0 x 8 is 0 and 9 x 8 is 72 so when you multiply the two together you get 720.
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
24
Step-by-step explanation:
Answer:(x+1)(x+14)
Step-by-step explanation:
