The vector pq is given by:
pq = q - p = (7.3) - (5.4)
pq = (7-5, 3-4)
pq = (2, -1)
The vector rs is given by:
rs = s - r = (4,1) - (8.6)
rs = (4-8, 1-6)
rs = (-4, -5)
Then, the vector pq + 3rs is given by:
pq + 3rs = (2, -1) + 3 (-4, -5)
pq + 3rs = (2, -1) + (-12, -15)
pq + 3rs = (2-12, -1-15)
pq + 3rs = (-10, -16)
Answer:
The component from the vector pq + 3rs is:
pq + 3rs = (-10, -16)
(Pay attention to the subject you're choosing, this is supposed to be in the Chemistry section, not here in the Mathematics)
On the periodic table, the Magnesium Mg is located in period 3, group 2. So it got 12 electrons.
So to become the cation Mg2+, the Magnesium has lost 2 electrons during it's formation.
So 12-2=10.
So there's 10 electrons in the Cation magnesium Mg2+
Hope this Helps! :)
Answer:659.64 feet
Step-by-step explanation:
We are given that a cell phone tower is anchored by two cables on each side for support. The cables stretch from the top of the tower to the ground, with each being equidistant from the base of the tower so first of all we have to draw a diagram for this scenario as shown below figure 1
Next we are given that angle of depression from the top of the tower to the point in which the cable reaches the ground is 23 degrees as shown in figure 2
So from here we can conclude that as tower is 140 feet tall and the base angle between cable and ground would be also 23 degrees
so we just the trigonometric identity to find x
tan(theta) = opposite over hypotenuse
we know the angle theta = 23
opposite = 140 ( height of tower)
and base is the distance on one side of tower
so finally tan 23 = 140/x (tan = opposite over adjacent)
doing cross multiplication we get
x = 140 / tan 23
x = 329.82(rounded to hundredth)
so total ground distance between the cables = 2x = 2(329.82) = 659.64 feet