Question

Help please! Figure ABCD is a rectangle. Find the value of x.

Answer 1

Hello!

$\large\boxed{x = 2}$

As the figure is a rectangle, AE ≅ EC.

AE = x + 11

EC = 6x + 1

Set the two equal to each other:

x + 11 = 6x + 1

Subtract x from both sides:

11 = 5x + 1

Subtract 1 from both sides:

10 = 5x

Divide both sides by 5:

10/5 = 5x/5

x = 2.

Answer 2

⠀⠀⠀⠀⠀⠀☆☞Diagram☜☆

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$\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1,4)\qbezier(1,4)(1,4)(6,4)\qbezier(6,1)(6,1)(6,4)\qbezier(6,4)(6,4)(1,1)\qbezier(1,4)(1,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf D}\put(1.4,4.3){\sf B}\put(6.6,4.3){\sf C}\put(3.4,2){\sf E}\put(1.5,2){\sf x + 11}\put(4.75,3){\sf 6x+1} {\boxed{\bold{X = ??}}}\end{picture}$

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AnswEr :

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• The value of x is 2

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➤ How to solve ?

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For solving such problems we need to recall some rules and properties of quadrilateral .

Above given figure is a figure of an rectangle . We know that the diagonals of an rectangle bisect each other

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Bisect is refer to dividing the line into 2 equal parts .

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From this property of the rectangle ; we can observe in the given rectangle that

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⠀⠀⠀⠀⠀⠀⠀⠀AE = EC

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Solution :

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As , AE = EC

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➠ x + 11 = 6x + 1

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➠ x - 6x = 1 - 11

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➠ -5x = - 10

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➠ 5x = 10

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➠ x = 10/5

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➠ x = 2

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∴ The value of x is 2 .

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