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Nady [450]
3 years ago
12

The tarnish that forms on objects made of silver is solid silver sulfide; it can be removed by reacting it with aluminum metal t

o produce silver metal and solid aluminum sulfide. How many moles of the excess reactant remain unreacted when the reaction is over if 5 moles of silver sulfide react with 8 moles of aluminum metal? Hint: Write a balanced chemical equation first. Enter to 1 decimal place.
Chemistry
1 answer:
muminat3 years ago
3 0

Answer:

4.7 moles

Explanation:

Equation of reaction:

3Ag2S + 2Al = 6Ag +Al2S3

From the equation of reaction above,

3 moles of silver sulfide reacted with 2 moles of aluminum metal

Therefore, 5 moles of silver sulfide is required to react with (5×2/3 = 3.3 moles) of aluminum metal

The excess reactant is aluminum metal

Number of moles of aluminum metal that remain unreacted = 8 moles - 3.3 moles = 4.7 moles (to 1 decimal place)

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Answer:

141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.

Explanation:

Molarity is a measure of concentration of a solution that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.

So 2.30 mol / L indicates that 2.30 moles dissolve in 1 L of solution. You want to know in what volume is contained 0.325 mol of solute. For this you apply the following rule of three: if 2.30 moles of solute are present in 1 L of solution, 0.325 moles in how much volume is it?

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<u><em>141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.</em></u>

5 0
3 years ago
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