Answer:
132.17 g
Explanation:
The reaction given , in the question is -
CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S ( g )
From the reaction , 4 mole of S is required for the production of 1 mole of CS₂ .
since ,
Moles of CS₂ = given mass of CS₂ / Molecular weight of CS₂
Since ,
the Molecular weight of CS₂ = 76
Given , mass of CS₂ = 72.57 g
Moles of CS₂ = 72.57 / 76 = 0.95 mol
Since ,
The yield is 92.0 % .
Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles
Mass of S required = 4.13 * 32 = 132.17 g .
Answer is: 48,25 torr.
Raoult's Law: p = x(solv) · p(solv)
p - <span>vapour pressure of a solution.
</span>x(solv) - <span>mole fraction of the solvent.
</span>p(solv) - <span>vapour pressure of the pure solvent.
</span>n(ethanol) = 950g ÷ 46,07g/mol = 20,62 mol.
x(solv) = moles of solvent ÷ total number of moles
x(solv) = 20,62 ÷ 21,77 = 0,965.
p = 0,965 ·50,0 torr = 48,25 torr.
Tendons<span> may also attach muscles to structures such as the eyeball. A </span>tendon<span> serves to move the bone or structure. A </span>ligament<span> is a fibrous connective tissue which attaches bone to bone, and usually serves to hold structures together and keep them stable.</span>
Answer:
The final temperature of the iron is:- 38.0 °C
Explanation:
The initial temperature = 24.7 °C
Let Final temperature = T °C
Using,
Q = m C ×ΔT
Where,
Q is the heat absorbed by the iron = 85.7 J
C gas is the specific heat of the iron = 0.45 J/g °C
m is the mass of iron = 14.3 g
ΔT is the change in temperature. ( T - 24.7 ) °C
Applying the values as:
<u>Q = m C ×ΔT </u>
85.7 J = 14.3 g × 0.45 J/g °C × ( T - 24.7 ) °C
Solving for T, we get that:-
T = 38.0 °C
<u>The final temperature of the iron is:- 38.0 °C</u>
