Question

Calculate the volume of a 2.30 mol/L solution of Na2CO3 that contains 0.325 mol of solute.

Answer 1

Answer:

141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.

Explanation:

Molarity is a measure of concentration of a solution that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.

So 2.30 mol / L indicates that 2.30 moles dissolve in 1 L of solution. You want to know in what volume is contained 0.325 mol of solute. For this you apply the following rule of three: if 2.30 moles of solute are present in 1 L of solution, 0.325 moles in how much volume is it?

$volume=\frac{0.325 moles*1L}{2.30 moles}$

volume= 0.141 L

Being 1L=1000 mL, then 0.141 L=141 mL

141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.