Question

i haven't submitted a single assignment for this class since winter break bc i didn't realize she was assigning things on goformative and not schoology and now we're on trigonometric ratios i'm confused help me ​

Answer 1

Answer and Step-by-step explanation:

Trigonometric Function (These only work for right triangles):

SOH-CAH-TOA

S = Sine = sin

C = Cosine = cos

T = Tangent = tan

O = Opposite (side)

H = Hypotenuse (side)

A = Adjacent (side)

SOH = sin(angle) = $\frac{opposite}{hypotenuse}$

CAH = cos(angle) = $\frac{adjacent}{hypotenuse}$

TOA = tan(angle) = $\frac{opposite}{adjacent}$

1. sinQ (Q is the angle) = $\frac{14}{50} = \frac{7}{25} = 0.28$

Use Pythagorean Theorem to find side PQ.  $14^{2} + PQ^{2}= 50^{2} \\PQ^{2} = 2304\\PQ = 48$

2. cosQ = $\frac{48}{50} = \frac{24}{25} = 0.96$

3. tanQ = $\frac{14}{48} = \frac{7}{24} = 0.29$