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2 years ago

15

Factor each trinomial. Then match the polynomial (term) on the left with its factored form (definition) on the right. (4 points)

Group of answer choices x2 − 4x − 12 [ Choose ] x2 + 4x − 12 [ Choose ] x2 − x − 12 [ Choose ] x2 − 7x − 12 [ Choose ] i will give 40 points

1 answer:

Aloiza [94]2 years ago

8 0

Answer:

Your input: factor x2+4x+3.

To factor the quadratic function x2+4x+3, we should solve the corresponding quadratic equation x2+4x+3=0.

Indeed, if x1 and x2 are the roots of the quadratic equation ax2+bx+c=0, then ax2+bx+c=a(x−x1)(x−x2).

Solve the quadratic equation x2+4x+3=0.

The roots are x1=−1, x2=−3 (use the quadratic equation calculator to see the steps).

Therefore, x2+4x+3=1(x+1)(x+3).

(x2+4x+3)=1(x+1)(x+3)

Step-by-step explanation:

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What fraction makes the equation true?<br> Enter the answer in the boxes.<br><br> 5/6x =20/24

Darina [25.2K]

Answer:

x=1

Step-by-step explanation:

To find the value of x, we have to move all the real numbers to the other side.

5/6x = 20/24

We have divide each side by 5/6. Once we do that, we get—

x = 4/4

x = 1

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3 years ago

Simplify the radical

mamaluj [8]

Answer:

$9d^3$

Step-by-step explanation:

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1 year ago

Find the missing number (1+_ ÷7+4)÷8=4/7

GaryK [48]

The answer to (1+_÷7+4)÷8= 4/7 is -3 I believe

3 0

3 years ago

11 POINTS PLZ HELP EMERGENCY

Bad White [126]

Part A

The given expression is:

$(-5(1+2i)+3i(3-4i)$

We expand to get:

$-5-10i+9i-12i^2$

Note that $i^2=-1$

$12-5-10i+9i$

$-5-10i+9i+12$

$7-i$

Part Bi)

The given expression is;

$\sqrt{-50}$

We simplify to get:

$\sqrt{25\times 2\times -1}$

$\sqrt{25\times} \sqr{2}\times \sqrt{-1}$

Note that:

$\sqrt{-1}=i$

$5\sqr{2}i$

This is now of the form $a+bi$ , where $a=0,b=5\sqr{2}$ .

This explains why it is a complex number;

Part bii)

The given expression is :

$\frac{\sqrt{-50} }{\sqrt{5}}$

We simplify to get

$\sqrt{\frac{-50 }{5}}$

$\sqrt{-25}$

$\sqrt{-25}=\sqrt{25}\times \sqrt{-1}$

$\sqrt{-25}=5\times i$

$\sqrt{-25}=5i$

Part C

We want to simplify:

$i^{22}$

We rewrite in terms of $i^2$

$i^{22}=(i^2)^{11}$

$i^{22}=(-1)^{11}$

$i^{22}=-11$

5 0

3 years ago

The length of an object’s shadow varies directly with its height. If a can that is 13 cm tall casts a shadow that is 7.5 cm long

Gekata [30.6K]

True. because =

13÷7.5=1.73333
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4 0

3 years ago