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Harlamova29_29 [7]
2 years ago
8

Use a left-hand sum with 3

Mathematics
1 answer:
Alborosie2 years ago
6 0

Explanation

N x = 32 ]

sub intervals Lo ( [

Loft-hand: X2 X=> Siam = 23 x [sinot sin ? t sin

= xLot = x3

1.81

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From a rope 11m long two pieces of lengths 13/5m and 33/10m are cut off. What is the length the remaining rope?
Serhud [2]

Answer:

\frac{51}{10}m

Step-by-step explanation:

Given parameters:

  Length of rope = 11m

 First length cut off = \frac{13}{5}m

  Second length cut off = \frac{33}{10}m

Unknown:

Remaining length  = ?

Solution:

Let us find the total length cut off first;

       =     \frac{13}{5}m   +  \frac{33}{10}m

         = \frac{26 + 33}{10}

          = \frac{59}{10}m

So,

 Remaining length  = 11 -  \frac{59}{10}

                                 = \frac{110 - 59}{10}  

                                 = \frac{51}{10}m

5 0
3 years ago
What is (-36)^5/2 please help!!
Allisa [31]

Answer:

-7776

is the answer

that's the answer dude

4 0
3 years ago
Read 2 more answers
There are 2 rectangles. One was 1.2 cm by 3.4 cm. The other was measured 2.1 cm by 1.7 cm. How much is the perimeter?
ELEN [110]

Answer: See explanation

Step-by-step explanation:

Perimeter of a rectangle is given as:

= 2(length + breadth)

First rectangle measures 1.2 cm by 3.4 cm. The perimeter will be:

= 2(1.2+ 3.4)

= 2(4.6)

= 2 × 4.6

= 9.2cm

Second rectangle measured 2.1 cm by 1.7 cm. The perimeter will be:

= 2(2.1 + 1.7)

= 2 × 3.8

= 7.6cm

Total perimeter = 9.2cm + 7.6cm = 16.8cm

3 0
3 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
Type an inequality statement using the < or > for the inequality symbols solve for x 6x-11-13x<7-5x
lozanna [386]

Answer:

-9 < x

Step-by-step explanation:

6x-11-13x<7-5x

Combine like terms

-11-7x<7-5x

Add 7x to each side

-11-7x+7x<7-5x+7x

-11 < 7+2x

Subtract 7 from each side

-11-7 < 7-7+2x

-18 < 2x

Divide by 2

-18/2 < 2x/2

-9 < x

4 0
4 years ago
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