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olchik [2.2K]
2 years ago
11

Find the equation of the linear function represented by the table below in slope-intercept form.

Mathematics
1 answer:
alexandr402 [8]2 years ago
3 0

Answer: The equation is y = 3x + 3

Step-by-step explanation:

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What is the value of n?<br>enter answer in box​
nalin [4]

Answer:

6!

Step-by-step explanation:

chord x chord = chord x chord

(5) (n+8) = (7) (n+4)

i just started plugging in numbers

(5) (6+8) = (7) (6+4)

5 x 14 = 7 x 10

70=70

4 0
3 years ago
What is the slope of у&gt;- 2х + 3
charle [14.2K]

Answer:

-2x

Step-by-step explanation:

Graph

y > −2x + 3

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

y = mx + b

Find the values of m and b using the form y = mx + b. m = −2

b = 3

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: −2

intercept: (0, 3)

Graph a dashed line, then shade the area above the boundary line since y is greater than

−2x + 3.

y > −2x + 3

8 0
3 years ago
Geometry help. Inscribing circle help and constructing lines.
prohojiy [21]
<h3>1. Inscribe a circle ΔJKL. Identify the point of concurrency that is the center of the circle you drew. </h3>

To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.

1. Draw the angle bisector of angle JKL. The straight line in the green one.

2. Draw the angle bisector of angle KLJ. The straight line in the blue one.

3. Draw point D at these two lines.

4. Draw a line through point D perpendicular to side JK. The straight line in the red one.

5. Mark point G at the red line and side JK.

6. Draw a circle with center at D (point of concurrency) and a radius of DG.


<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>

To circumscribe a circle in the attached triangle, we must follow the following steps:

1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.

2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.

3. The center of the circle is the intersection of these two lines

4. Draw a circle with center at D (point of concurrency).

<h3>3. Construct the two lines tangents to circle</h3>

A tangent to a circle is a straight line that touches the circle at an only point. If a point A is outside a circle, we can draw two lines that pass through this point and are tangent to the circle at two different points each. So this is shown in the third figure. Lines red and blue are tangent to the circle at two different points.

3 0
3 years ago
Which answer is equal to 2sqrt-28?
Oksana_A [137]

2^2-28

=4-28

=-24

that is it

4 0
3 years ago
Evaluate The Exsperession. Show your work<br><br><br>6.7-3^2.9+4^3<br>or
Rom4ik [11]
  • <em>Answer:</em>

<em>25</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>6×7 - 3²×9 + 4³ =</em>

<em>   1. raise the numbers to power</em>

<em>= 6×7 - 9×9 + 64</em>

<em>   2. we perform the multiplications</em>

<em>= 42 - 81 + 64</em>

<em>   3.  we perform addition and subtraction</em>

<em>= (42 + 64) - 81</em>

<em>= 106 - 81</em>

<em>= 25</em>

<em>Good luck !</em>

7 0
3 years ago
Read 2 more answers
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