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Bezzdna [24]
2 years ago
12

The first three terms of an arithmetic sequence are given. Find an expression for tn in terms of n, and write the tenth term for

each sequence. PLEASE HELP ASAP!!
a, 2a, 3a, . . .

tn = ?
t10 = ?

THANK YOU!!!!!!!!!!!!!!!!
Mathematics
2 answers:
ser-zykov [4K]2 years ago
5 0

Answer:

  tn = n·a

  t10 = 10a

Step-by-step explanation:

We observe that the coefficient of 'a' is the term number:

  tn = n·a

  t10 = 10a

Gre4nikov [31]2 years ago
4 0

Answer:

tn = n·a

 t10 = 10a

Step-by-step explanation:

We observe that the coefficient of 'a' is the term number:

 tn = n·a

 t10 = 10a

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Justify each step in solving the equation -3(2x-3)=25-8x by writing a reason for each statement.
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Answer: x= 8.


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Step 1: We have -3 in front of (2x-3). We always simplify a parenthesis first.

Therefore, applying Distributive property in first step, we get

-6x +9 = 25-8x.

Step 2:  We need to get rid 9 from left side to get constant numbers on right side.

9 is being added on left side.

So, we would apply reverse operation of addition.

Therefore, applying Subtraction property of equality, we get

-6x +9-9 = 25-8x-9

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Step 3: We need to get rid 8x from right side.

The reverse operation of subtraction is addition.

Therefore, applying Addition property of equality, we get

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Step 4: We need to isolate it for x.

So, applying Division property of equality, we get

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