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Alchen [17]
3 years ago
13

In order to measure the dispersion of a random variable, look at its a. standard deviation. b. mean. c. expected value. d. avera

ge.
Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0

Answer:

a. standard deviation

Step-by-step explanation:

Dispersion is a measure of variability in a given data i.e the level or extent of spread of a data. This can easily be measured for a random variable by considering its standard deviation.

The standard deviation would show the extent to which each value is different from the mean. Thus showing the extent of the dispersion of variables.

Therefore, to measure the dispersion of a random variable, look at its standard deviation.

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Of the 528 clients at Bernie's salon, 122 of them have black hair. What is the probability that a randomly selected client at Be
EleoNora [17]

The probability that a randomly selected client at Bernie's salon has black hair is 61 / 264.

<h3>What is the probability?</h3>

Probability measures the odds that a stated event would occur. The odds the event happens lies between 0 and 1.

The probability that a client at Bernie's salon has black hair = number of clients with black hair / total number of clients

122 / 528 = 61 / 264

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

5 0
2 years ago
4<br>_ compared to 0.45 <br>9
malfutka [58]

Answer:

<

Step-by-step explanation:

\dfrac{4}{9}=0.\overline{4}

The tenths-place digits of the two numbers are the same, 4. So comparison proceeds to the hundredths place. The digit in the hundredths place of 0.4444... is 4, which is less than the digit in the hundredths place of 0.45, which is 5. Hence 4/9 < 0.45.

8 0
3 years ago
Round to the nearest whole number: 123.45
koban [17]

Answer:

123

Step-by-step explanation:

because if its lower than 50 you round down, if its 50 or above you round up

8 0
3 years ago
Read 2 more answers
Please help it’s just for A4 ignore All the other problems the equation is c=0.15t+2.50
Semmy [17]

Answer:    sds\\ \\ x^{2} \geq \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n \geq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x^{2}  \lim_{n \to \infty} a_n \pi \neq \sqrt{x} \neq

Step-by-step explanation:i need the think points

4 0
3 years ago
75(1+0.2/12)^10*12 what is the answer
Alchen [17]

Answer:

545.119

Step-by-step explanation:

75 * (1 + .2/12)^10 * 12

75 * (1.016667)^10*12

Now things get a little tricky. What does 10*12 mean? I'm taking it to mean 120

75 * (1.016667)^120

75 * 7.268

545.119

8 0
3 years ago
Read 2 more answers
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