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Jet001 [13]
2 years ago
7

A quality control inspector routinely takes random samples of 200 cans of fruit cocktail produced in a packing

Mathematics
1 answer:
Butoxors [25]2 years ago
7 0

Answer:

A

Step-by-step explanation:

Khan Academy

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Sal and her three friends plan to bowl one or two games each. Each game costs $2.50 each. Identify the independent and dependent
tino4ka555 [31]
So the dependent is the number of games because it's not definite they dont know for sure. so the domain always involves money!!! always! the range wiyld be the numbers they migh play like 8-10 so 4 to 8 is the range value. so determining off of that the indepedent variable would be the total cost becuase it wont change so your answer is C hope this helped have a good day!!!
3 0
2 years ago
Read 2 more answers
At what value of x does the graph of the following function F(x) have a
Free_Kalibri [48]

Answer:

B

Step-by-step explanation:

Given

f(x) = \frac{1}{x+2}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

6 0
3 years ago
If X+Y = 2 and the square root of (X^2 + Y^2) = 10 find X, Y
kondor19780726 [428]
X+y = 2

(2*2 + 2*2) 
(4 + 2*2)
(4 + 4)
= 8
4 0
2 years ago
ASAP ANZWER PleASEEE :)
Hitman42 [59]

Answer:

%80

Step-by-step explanation:

5 0
2 years ago
The volume of a right cone is 17287 units³. If its circumference measures 247 units,
Nikolay [14]

The height of the right cone is 10.68 unit

<h3>What is Volume ?</h3>

Volume is defined as the space occupied by a three dimensional object.

Volume of a right cone is given  by

V = π r²h/3

C = 2 π r

r = 247/2 π

3 * 17287 =  π  r²h

3 * 17287 =  π *(247/2 π )²h

h = 51861 *π *4/61009

h = 10.68 unit

Therefore the height of the right cone is 10.68 unit.

To know more about Volume

brainly.com/question/1578538

#SPJ1

7 0
2 years ago
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