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NeTakaya
3 years ago
13

A bank account has $900 in it. Every week, Bob withdraws $45 to pay for his car's gas. What is the maximum number of weeks that

Bob can withdraw the money so there is at least $120 remaining in the account? Write an inequality to find the solution
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

hdeh

Step-by-step explanation:

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(02.05 MC)
Amiraneli [1.4K]

Table for f(x)

\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf f(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 9\\ \sf 4 &\sf 17\end{array}}

Table for g(x)

\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf g(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 7\\ \sf 4 &\sf 13\end{array}}

Option C is correct

3 0
3 years ago
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What is the cost of nine ounces of cheese at $0.80 per pound?
alina1380 [7]

Answer:

0.45

Step-by-step explanation:

$0.80/16 * 9

3 0
4 years ago
Just need this cheeked
Ganezh [65]
If two angles are complementary, then the sum of their measures is 90

If the sum of their measures is 90, then the two angles are complementary.
7 0
3 years ago
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Trivikram jogs from one end of corniche to its other end on a straight 300 m road in 2 minutes 50 seconds and then turns around
alekssr [168]

Answer:

1.76m/s ; 1.76m/s ; 1.74m/s, 0.86m/s

Step-by-step explanation:

Given the following :

Distance jogged in first direction (A to B) = 300m

Time taken = 2 minutes 50s = (2*60) + 50 = 120 + 50 = 170s

Distance jogged in opposite direction (B to C) = 100m

Time taken = 1minute = 60s

Recall:

Speed = distance / time

Therefore Average speed from A to B

Average speed = 300m/ 170s = 1.764 = 1.76m/s

Average Velocity = Displacement / time

Displacement = 300m ; time = 170s

= 300m / 170s = 1.76m/s

Average speed (A to C)

Therefore, average speed = total distance / total time taken

Total distance = (300 + 100)m = 400m

Total time taken = (170 + 60)s = 230s

Average speed = 400m / 230s

= 1.739m/s = 1.74m/s

Average velocity:

Displacement = distance between initials position and final position.

Initial distance covered = 300m. Then 100m was jogged in the opposite direction.

Distance between starting and ending positions, becomes : (300 - 100)m = 200m

200 / 230 = 0.87m/s

7 0
3 years ago
ALL MY POINTS PLZ BE RIGHT
shepuryov [24]

Answer:

-xy^6 +2y -6

Step-by-step explanation:

(-6x^2 y^8+12xy^3-36xy^2)

-------------------------------------------

6xy^2

Divide each term by 6 in the numerator and denominator

(-6/6x^2 y^8+12/6xy^3-36/6xy^2)

-------------------------------------------

6/6xy^2

-x^2y^8 +2xy^3 -6xy^2

---------------------------------

xy^2

Divide each term by x in the numerator and denominator

-x^2/xy^8 +2x/xy^3 -6x/xy^2

---------------------------------

x/xy^2

-xy^8 +2y^3 -6y^2

---------------------------------

y^2

Divide each term by y^2 in the numerator and denominator

Remember when dividing, we subtract the exponents

-xy^8/y^2 +2y^3/y^2 -6y^2/y^2

---------------------------------

y^2 /y^2

-xy^6 +2y^1 -6

---------------------------------

1

-xy^6 +2y -6

7 0
3 years ago
Read 2 more answers
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