Answer:
A Hercules Beetle is 6.97 inches larger than A ladybug
Step-by-step explanation:
A hercules beetle is 7 inches long while a ladybug is about 0.03 cm long when subtracting these two you will get a grand total of 6.97.
The correct answer will be 5z^3
P is less than or equal to (<) 110-52 you want to use the < sign with a line under it. The minus 52 is because he has already thrown 52 out of his 110 and P is how many pitches he is alloted
36;
the square root and the square cancel out, or you can work it out and say
((36)^1/2)^2 = (6)^2= 36
