Question

Please help cant find anywhere

Answer 1

Answer:

The option is first one that is

$\frac{m^{7}n^{3}n}{m}$

Step-by-step explanation:

Given:

$\frac{m^{7}n^{3}}{mn^{-1} },m\neq 0,n\neq 0$

After negative exponent eliminated we get

$\frac{m^{7}n^{3}n}{m}$

Negative exponent :

The variable containing negative powers. Here the variable( n⁻¹) is negative exponent.

Law of indices

$a^{-1} = \frac{1}{a}\\\\Here\\n^{-1} = \frac{1}{n}$

$\\\textrm{Using law of indices we get}\\\frac{m^{7}n^{3}}{mn^{-1} }=\frac{m^{7}n^{3}}{m\frac{1}{n} } }\\\\ \frac{m^{7}n^{3}}{mn^{-1} }=\frac{m^{7}n^{3}n}{m}$