All categories

3 years ago

Triangle DEF is an isosceles triangle.

Mathematics

1 answer:

sergiy2304 [10]3 years ago

8 0

Answer:

<E = 154°

Step-by-step explanation:

As we can see it is an isosceles triangle so

base angles are equal Then

13° + 13° + < E = 180° < Being sum of angles of triangle >

<E = 180° - 13° - 13°

Therefore <E = 154°

You might be interested in

Bobby eats at a restaurant and his bill comes out to $45.50. He liked his server and decides to leave a 20% tip.

S_A_V [24]

Answer:

$54.60

Step-by-step explanation:

45.50*.20=9.10

9.10+45.50=54.60

8 0

3 years ago

Read 2 more answers

Which line has a slope of -5/8 and goes through the point (2,-3)

Kamila [148]

Answer: y = -5x/3 - 7/4

Step-by-step explanation:

The equation of a line in slope and point form is given as

y - $y_{1}$ = m(x - $x_{1}$ )

where m is the slope

$x_{1}$ = 2

$y_{1}$ = -3

m = -5/8

Substituting into the formula , we have

y - ( -3 ) = -5/8 ( x - 2 )

y + 3 = -5x/8 + 5/4

This could also be written in slope - intercept form , that means we will make y the subject of the formula

y = -5x/8 + 5/4 - 3

y = -5x/3 - 7/4

4 0

4 years ago

Which list shows all the positive factors of 23? 1,3,23 1,23 1,2,3,23 1,2,23

forsale [732]

<span>1,23 i think it may be this
</span>

8 0

3 years ago

A rate that describes how much smaller or larger the scale drawing is than then real object

Tems11 [23]

I'm not sure what is being asked here, but a rate that describes how much smaller or larger the scale drawing is than the real object would be a ratio such as 1in:25ft

6 0

4 years ago

In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0

4 years ago