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zloy xaker [14]
3 years ago
11

A third line intersects two lines (A transversal). Which condition would always make the two lines parallel?

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0
It is c corresponding
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Anyone need 30 points?
postnew [5]

Answer:uh kinda

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
7.80×10^7/1.0×10^4=?​
spin [16.1K]

Answer:780000000000

Step-by-step explanation:7.80×10^7/1.0×10^4=?​

7 0
3 years ago
Pls solve part b) iii thanks
Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees

Read more about bearings at:

brainly.com/question/24142612

#SPJ1

4 0
2 years ago
Francesca ran five times as many miles as sophia last year. They ran a total of 3,455 miles. How many miles did each girl run la
uysha [10]

Answer:

  • Francesca: 2879 1/6 miles
  • Sophia: 575 5/6 miles

Step-by-step explanation:

For each mile that Sophia ran, Francesca ran 5 miles. Then Sophia ran 1/6 of their total. Sophia ran ...

  (1/6)(3455) = 575 5/6 miles

Francesca ran the remaining miles:

  3455 -575 5/6 = 2879 1/6 miles

7 0
3 years ago
Suppose you take a simple random sample of size n=175 from the population of Reese's Pieces, still assuming that 45% of this pop
Gnesinka [82]

Answer:

The  probability is  P(0.35

Step-by-step explanation:

From the question we are told that

  The sample size is  n =  175

   The population proportion is  p =  0.45

   

Generally the mean of the sampling distribution is  \mu_{x} =  0.45

 Generally the standard deviation is mathematically represented as  

        \sigma_{x} =  \sqrt{\frac{p (1-p)}{n} }

=>      \sigma_{x} =  \sqrt{\frac{0.45 (1-0.45)}{175} }

=>      \sigma_{x} = 0.0376

Generally the probability of  that the sample proportion of orange candies will be between 0.35 and  0.55 is  

      P(0.35 <  X < 0.55) =  P( \frac{0.35 - 0.45}{0.0376} <  \frac{X -\mu_{x}}{\sigma_{x}}  <  \frac{0.55 - 0.45}{0.0376} )

=>   P(0.35

Generally \frac{X - \mu_{x}}{\sigma_{x}}  =  Z  (The \  standardized \  value \  of  X)

So

    P(0.35

=>  P(0.35

From the z-table  

    P(  Z< 2.6595 ) = 0.99609

and

    P(  Z< - 2.6595 ) = 0.0039128

So

   P(0.35

=> P(0.35

3 0
3 years ago
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