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statuscvo [17]
3 years ago
13

Nadine has a plastic container in the shape of a prism that is filled with beads. The container has a length of 6 inches, a widt

h of 8 inches, and a height of
5 inches
The container has a crack, so she needs to move all of the beads to new containers that are also rectangular prisms. Determine which sets of containers she could use for
the beads.
Select Yes or No for each set of containers.

Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

BTW C= containers and AC = area of all the containers all together.

Step-by-step explanation:

So first off you calculate the area of the container that had a crack so its

Width X Length X height    |   6 x 8 x 5 = 240

So then you look at the possible answers and then calculate the area of those   plastic containers. So then you start with the first one and it would be like this

First possible answer: 3 and 1/3  x 6 x 5 = 100 x 3c = 300ac

Second possible answer: 2 and 1/4 x 4 and 3/4 x 6 = 64.125 x 4c = 256.5ac

Third possible answer: 3.5 x 6.5 x 6 = 136.5 x 2c = 273ac

Fourth possible answer: 3 and 1/2 x 3 and 1/4 x 5 = 56.875 x 5c = 284.375ac

Hopefully this will help you find your answer!! I tried my best!! Please give brainly!!

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vovikov84 [41]
Well the ratio would be 8:24, or in reduced form, 1:3. you would solve it by taking sale of strawberry yogurt for the first half of the ratio, and then adding up all of the values to get the total.
5 0
3 years ago
An amateur radio operator erects a 75-foot vertical tower for an antenna. A 117 guy wire is pulled from the top of the tower dia
vitfil [10]

Answer:

α=39.80°

Step-by-step explanation:

applying the law of sin and cos, we have:

sin\alpha =\frac{75}{117}=0.6410\\\alpha =acs(0.64)= 39.79

and to the nearest tenth of a degree

α=39.80°

3 0
3 years ago
Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,
Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{-5}^{-5}\int_{-5}^5x^6e^y(25-y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\left(\int_{-5}^5x^6\,\mathrm dx\right)\left(\int_{-5}^5e^y(25-y^2)\,\mathrm dy\right)=\boxed{\frac{625,000(3+2e^{10})}{7e^5}}

4 0
3 years ago
The pressure of a gas p(v) varies inversely with the volume of gas v. the pressure of a gas measures 8kg/cm^2 when its volume is
Artist 52 [7]

Answer:

B

Step-by-step explanation:

Since p and v vary inversely then the equation relating them is

p = \frac{k}{v} ← k is the constant of variation

to find k use the condition p = 8 when v = 40

k = pv = 8 × 40 = 320

⇒ p(v) = \frac{320}{v} → B


7 0
3 years ago
Read 2 more answers
6 & 7 please help me show work please and thank you!
lara31 [8.8K]

Answer:

6. \frac{29}{15} or 1\frac{14}{15}

7. \frac{133}{96} or 1\frac{37}{96}

3 0
3 years ago
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