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2 years ago

Please helpppp i don’t understand

Mathematics

1 answer:

atroni [7]2 years ago

5 0

Answer:

Think the answer will just be 5

Step-by-step explanation:

I don't use step by step so yeah

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If you are driving at a constant speed of 96 kilometers per hour, how long will it take you to travel 288 kiloneters?

larisa86 [58]

Answer:

3 hours

Step-by-step explanation:

288 ÷ 96 km/h = 3 hours

as time = distance ÷ speed

6 0

3 years ago

Read 2 more answers

Please answer this question!

bogdanovich [222]

it's answer is 82 but I think

it will wrong

5 0

2 years ago

Precal help if you could could you answer both. Me finishing this helps me graduate.

oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

$z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))$

In this form, you have

$z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))$

The magnitude of the number is given by

$z=a+bi \implies \rho = \sqrt{a^2+b^2}$

So, we have

$z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2$

As for the angle, we have

$z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}$

So, we have

$z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}$

Finally,

$z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64$

Exercise 2:

You simply have to compute the trigonometric function:

$\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}$

So, we have

$z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i$

7 0

3 years ago

7. Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6). Determine whether

kirill [66]

Answer:

SQUARE

Step-by-step explanation:

If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).

Find the following MN, NP, PQ and MQ

Using the formula for calculating the distance between two points

MN = √(6-0)²+(0-4)²

MN = √6²+4²

MN = √36+16

MN = √52

MN = 2√13

NP = √(0-6)²+(-4-0)²

NP = √6²+4²

NP = √36+16

NP = √52

NP = 2√13

PQ = √(-6-0)²+(0-(-4))²

PQ = √6²+4²

PQ = √36+16

PQ = √52

PQ = 2√13

MQ = √(-6-0)²+(0-4)²

MQ = √6²+4²

MQ = √36+16

MQ= √52

MQ = 2√13

Since the length of all the sides are equal, hence the shape is a SQUARE

4 0

2 years ago

Which set of numbers could represent the lengths of the sides of a right triangle?

vitfil [10]

in this problem what you are really looking for is which of these sets is a pathagorean triple. That means it will solve the pathagorean theorem. (a sqaured + b squared = c squared) c is always going to be the largest number or the hypotenuse. if you plug all the number sets into the theorem, only one works and that is 7, 24, 25 which is your answer.

4 0

3 years ago