Answer:
Part 1. 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.
Variable x denotes the number of shifts at the dinner and y variable denotes the number of dog -walking job.
Part 2. The income from shift of work at the diner that is 50x, and the income from dog walking work that is 17y.
Part 3. The total income from the diner is given by 50x.
Step-by-step explanation:
Each week, Aubrey earns $50 for every shift he works at the diner and $17 for every dog-walking job.
He uses the expression (50x + 17y) to keep track of his earning.
Part 1. Here the coefficient of the expressions 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.
And the variable x denotes the number of shifts at the dinner and y variable denotes the number of dog -walking jobs.
Part 2. Therefore, there are two terms in the expression, one is the income from the shift of work at the diner that is 50x and the other is the income from dog walking work that is 17y.
Part 3. The total income from the diner is given by 50x. (Answer)
If x-10=15 and x=25
then the Hypothesis would be true.
25-10=15
the answer if those two are the answers it'd be A.
The answer could be something of the sort like 2/24, because 1/12 can't be simplified, you would just keep multiplying both numbers until you get another fraction equal to 1/12
Pictures listed in order... from A-C
This is a fairly tedious problem. The only way to solve that I see is to simply list out all the possible cases and go through each one by one. You'll use the triangle inequality theorem to see if the triangles can be formed. The theorem says that a+b > c must be true for all sets of pairs. In other words, take any two sides and add them up. The sum must be greater than the third side.
Going through all the combos possible (that I could find), this is what I got
Blue9,Green7,Orange4
Blue9,Green7,Purple12
Blue9,Green7,Red3
Blue9,Green7,Yellow5
Blue9,Orange4,Purple12
Blue9,Purple12,Yellow5
Green7,Orange4,Yellow5
Green7,Red3,Yellow5
Orange4,Red3,Yellow5
In all, I count 9 cases. So the answer to problem 1 is 9.
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For problem 2, the best way may be to pick two segments at a time instead of one. However, I have a feeling that will take just as long as the first method. I haven't tried it out. Even though going through the rods one at a time takes a while, it's probably the best option so you don't overlook any cases.
