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4 years ago

-5÷(-3 1/3)= how do I solve this?

Mathematics

2 answers:

liberstina [14]4 years ago

8 0

Answer:

3/2 or 1.5

Step-by-step explanation:

Convert (-3 1/3) to -10/3

Now its -5/(-10/3)

The 3 is multiplied by the -5

(-5)(3)/(-10)

=(-15)/(-10)

The negatives cancel and it reduces to 3/2

abruzzese [7]4 years ago

6 0

the answer in Exact Form:

3/2

in Decimal Form:

1.5

in Mixed Number Form:

1 1/2

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How do u write this sentence as an inequality? A number c minus 3.4 is less than 14

Leno4ka [110]

C - 3.4 < 14 hope this helps!

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4 years ago

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Suppose your top drawer contains different colored socks: 14 are white, 4 are black, 12 are pink, and 8 are blue. All socks in t

Aleks [24]

Answer:

8/38

Step-by-step explanation:

38 - total

8 - blue

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3 years ago

Determine if the ordered pair is a solution to the equation. Y = -x - 2; (2,-4)

hoa [83]

Yes, the ordered pair (2,-4) is a solution to the equation.

2 = x
-4 = y

Subtitute x and y
-4=-2-2
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5 0

3 years ago

PI-3.

Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

$x=2q_1+1$

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

$x=3q_2+1$

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

$x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1$

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

$x=7q_6$

This means $x-1$ is divisible by 2, 3, 4, 5 and 6 without remainder, so

$x-1=2\cdot 3\cdot 2\cdot 5n=60n$

Hence,

$x=60n+1, \ n\in N$

The smallest amount of money they could have raised is $301, because

$x=60\cdot 5+1=301$ is divisible by 7.

Now, the number $x=60n+1$ should be divisible by 7 and must be greater than 500.

So,

$60n+1>500\\ \\60n>499\\ \\n>8$

When n = 9,

$x=60\cdot 9+1=541$ is not divisible by 7.

When n = 10,

$x=60\cdot 10+1=601$ is not divisible by 7.

When n = 11,

$x=60\cdot 11+1=661$ is not divisible by 7.

When n = 12,

$x=60\cdot 12+1=721$ is divisible by 7.

B. The least amount of money they could have raised is $721

7 0

3 years ago

Read 2 more answers

Let C be the curve which is the union of two line segments, the first going from (0, 0) to (1, -3) and the second going from (1,

Art [367]

Answer:

(C→)∫ -2 dy + 1 dx=2

Step-by-step explanation:

From Exercise we have :

(0, 0) to (1, -3) and (1, -3) to (2, 0).

(C→)∫ -2 dy + 1 dx

We will divide the given curve into two curves.

We find the parametric equation for the points (0,0) and (1,-3), we get

r(t)=(0,0)+t((1,-3)-(0,0))

r(t)=t(1,-3)

r(t)=(t,-3t) for 0≤t≤1.

We get

x=t ⇒ dx=dt

y=-3t ⇒ dy=-3dt

Now, we get

∫_{C_1} -2 dy + 1 dx=\int\limits^1_0 {-2·(-3)} \, dt +\int\limits^1_0 {1} \, dt =

=6\int\limits^1_0 {1} \, dt+\int\limits^1_0 {1} \, dt

=7\int\limits^1_0 {1} \, dt

=7· [t]^1_0

We find the parametric equation for the points (1,-3) and (2,0), we get

r(t)=(1,-3)+t((2,0)-(1,-3))

r(t)=(1,-3)+t(1,3)

r(t)=(1,-3)+(t,3t)

r(t)=(1+t,-3+3t) for 0≤t≤1.

We get

x=1+t ⇒ dx=dt

y=-3+3t ⇒ dy=3dt

Now, we get

∫_{C_2} -2 dy + 1 dx=\int\limits^1_0 {-2·(3)} \, dt +\int\limits^1_0 {1} \, dt =

=-6\int\limits^1_0 {1} \, dt+\int\limits^1_0 {1} \, dt

=-5\int\limits^1_0 {1} \, dt

=-5 [t]^1_0

=-5

Therefore, we get

(C→)∫ -2 dy + 1 dx=∫_{C_1} -2 dy + 1 dx+∫_{C_2} -2 dy + 1 dx

(C→)∫ -2 dy + 1 dx=7-5

(C→)∫ -2 dy + 1 dx=2

8 0

3 years ago

-5÷(-3 1/3)= how do I solve this?​

-5÷(-3 1/3)= how do I solve this?