All categories

3 years ago

How much force is needed to accelerate 250 kg at a rate of 6 m/s/s?

Physics

1 answer:

mash [69]3 years ago

7 0

Answer:

$1500 \: \mathrm{N}$

Explanation:

The equation $F=ma$ represents the force needed.

Plugging in $m=250$ and $a=6\: \mathrm{m/s^2}$ , we find that the force needed to accelerate a 250 kg object at a rate of $6 \: \mathrm{m/s^2}$ to be $\fbox{$1500 \: \mathrm{N}$}$ .

You might be interested in

What is the resultant of the vecotors shown?

Karolina [17]

D, I believe would be the first minus the second vector.

To solve this I named the first vector as A and the second as B.

So... vector A - B = resultant

or A + (-B)

A negative indicates a direction of a vector so if we flip the direction the other way we have the first vector (A) pointing vertically upwards and then vector B pointing to the west.

Now we have to use the head to tail method, meaning that the head of the first vector has to connect with the tail of the other vector added.

So we should have something like this

(-B) < - - - - ^

| (A)

To add these two vectors, technically A - B, draw a line from the tail of A to the head of -B which would look like image D.

Hope this helped!

3 0

4 years ago

Read 2 more answers

What does the person in front of the ambulance experience?

kow [346]

A higher frequency. I just got this answer on usa test prep.

6 0

3 years ago

Some kids are playing by rolling a skateboard across level ground beside a 0.75 m high wall. The goal is to drop from the wall v

lys-0071 [83]

Answer:

The speed of the kid and the skateboard together is 0.723 m/s

Explanation:

Let the mass of the kid be $m_{k} = 45 kg$

Let the mass of the skateboard be $m_{s} = 4,5 kg$

The initial speed of the skateboard, $v_{s} = 8 m/s$

The initial horizontal speed of the boy as he jumps on the skateboard, $v_{k} = 0 m/s$

Let the speed of the kid and the skateboard together be v

According to the principle of conservation of momentum:

$m_{k} v_{k} + m_{s} v_{s} = (m_{k} + m_{s}) v$

Substituting the appropriate values into the given equation

$(45*0) + (4.5*8) = (45 + 4.8) v$

36 = 49.8 v

v = 36/49.8

v = 0.723 m/s

7 0

4 years ago

I need help with question 26<br>this is from my physics textbook

Neko [114]

Suppose $a,b,c$ are measured in meters. Then the semiperimeter $s=\dfrac{a+b+c}2$ is also given in meters, so $s-a,s-b,s-c$ are all also given in meters. When multiplied together, $(s-a)(s-b)(s-c)$ is measured in cubic meters. Divide this by $s$ , measured in meters, and this reduces to square meters. Take the square root and you end up back with meters once again. So the formula is indeed dimensionally consistent.

6 0

4 years ago

An unwary football player collides with a padded goalpost while running at a velocity of 5.70 m/s and comes to a full stop after

ollegr [7]

The relationship between the initial velocity, final velociy, distance, and deceleration can be expressed in the following equation.

2(a)(0.270 m) = 0² - (5.70 m/s)²

The value of a (which is the deceleration) is 0.06 m/s². Thus, the answer is that the deceleration value is approximately 0.06 m/s².

6 0

4 years ago