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QveST [7]
3 years ago
12

Two angles are

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer: 126 Degrees

Step-by-step explanation: Two angles that are supplementary always equal 180 degrees which means all you have to do is 180-54 and that is your answer. Plz mark Brainliest :).

fredd [130]3 years ago
6 0
126 degrees is the answer
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PLZZZ HELPPP ME ASAP!!!
Sonja [21]

Answer:

Not a function.

Does not pass vertical line test.

B.

Step-by-step explanation:

Something called a vertical line test is used to determine if a relation that has been graphed is a function or not.

We say if it passes then it is a function.

It will pass if you are able to draw infinitely many vertical lines covering the whole graph and each vertical line either touches your relation once or none.  

If a single vertical line that you draw touches more than once, then it isn't a function.

When I say draw, I don't mean you should physically do it, but more so imagine it.

Now this particular relation is not a function because I can find a vertical line that touches more than once.  Take the vertical line x=5 for example.

It will touch at (5,-6) and (5,6). You cannot have an x assigned to more than one y.

4 0
3 years ago
the measure of the seven angels in an octagon measure 129, 132, 136, 124, 141, 158, and 116. what is the measurement of the last
Taya2010 [7]

Answer:

116

Step-by-step explanation:

IT SAYS WHAT IS THE MEASUREMENT OF THE LAST ANGLE 116 WHAT THE LAST NUMBER.

8 0
3 years ago
Find the equation of the line with slope m = 5/3 that contains the point (-6, -12)
Mice21 [21]

Answer:

3y-(-12) = 5(x-(-6)

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4 0
3 years ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
Unit 2, Lesson 12
Solnce55 [7]

Answer:

the answer for a is 2 and 2/4 which is equal to 2 and 1/2

Step-by-step explanation:

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