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Rasek [7]
3 years ago
12

PLEASE ANSWER AS SOON AS YOU SEE THIS

Mathematics
2 answers:
jeka57 [31]3 years ago
4 0

Answer:2

Step-by-step explanation:

lakkis [162]3 years ago
3 0

Answer:

4

Step-by-step explanation:

Divide 8 by 2 and you get 4.

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Giúp tôi với nhanh lên
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Step-by-step explanation:

7 0
3 years ago
Find approximate solution for the equation in the interval 0<_ x <_ pi. round to three decimal places. tanx=5 sin x
timofeeve [1]

Answer:

d. 0, 1.369

Step-by-step explanation:

Given:

The equation is: \tan x =5\sin x................(0\leq x\leq \pi)

Adding -5\sin x on both sides, we get

\tan x - 5\sin x=0

Using the identity \tan x=\frac{\sin x}{\cos x}, we get

\frac{\sin x}{\cos x}-5\sin x=0

Factoring out \sin x, we get

\sin x(\frac{1}{\cos x}-5)=0\\\\\therefore \sin x=0\ or\ \frac{1}{\cos x}-5=0\\\\x=\sin^{-1} (0)\ or\ \cos x=\frac{1}{5}\\\\x=0\ or\ x=\cos^{-1} (\frac{1}{5})\\\\x=0\ or\ x=1.3694\approx 1.369(\textrm{Round to 3 decimal places})

Therefore, the solution of the given equation is either 0 or 1.369.

The correct choice is d.

4 0
3 years ago
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